R中如何将一长列数值型数据按照一定的条件拆分成多列？

Question

我试图通过将每 12 个连续值（非重复）分配到一个新的（较短的）列中来拆分一列数值数据。任何帮助将不胜感激。

到目前为止我试过：

    df_all <- rnorm(500, mean = 5, sd = 1)  # example data, I didnt use this one
    df_final <- matrix(, nrow = 12, ncol = 0)
    
    for(i in seq(1, length(df_all), 12)) {
      x <- df_all[i:i+11]
      df_final <- data.frame(cbind(df_final, x))
    }

    write.csv(df_final, file = paste0(rootdir,"/","mT",'.csv'))

它不起作用，它将段“x”的第 12 个相同值附加到新列的所有 12 行。我检查了 df_all[1:12]，它返回正常的正确值。

Answer 1

你可以

df_all |>
  matrix(nrow = 12) |>
  as.data.frame()

返回（截断）：

         V1       V2       V3       V4       V5       V6       V7       V8
1  3.583938 6.071985 6.429908 4.632524 5.477596 4.548784 4.588537 5.487138
2  4.055486 5.828313 3.517980 7.242400 4.909442 6.149804 3.990672 6.752652
3  3.710380 4.001795 5.739687 3.479396 6.191938 5.578237 3.252641 6.070115
4  4.867136 5.191307 5.884153 4.647208 5.437753 3.455165 5.989859 7.442414
5  5.111246 5.882136 6.361230 5.186235 3.867077 5.631055 5.030219 4.595383
6  5.061778 5.560719 4.146807 5.341364 2.919934 3.305795 5.129994 6.159989
7  6.188377 4.606850 6.693071 6.997215 5.722066 5.307161 4.795347 5.122470
8  4.035036 4.785901 3.325937 4.907982 5.490938 6.416011 7.522089 6.845924
9  6.152382 3.506762 4.541983 4.166833 3.461948 4.155356 2.969548 4.585297
10 6.834143 5.818803 5.048908 2.944199 4.999610 4.892196 4.242976 4.337777
11 4.293846 4.744218 4.244750 4.261823 4.552857 3.965914 4.560048 4.257186
12 5.605399 6.246158 6.622988 7.637657 5.349231 4.258165 4.357449 5.635602

使用的数据：

df_all <- rnorm(500, mean = 5, sd = 1)

R中如何将一长列数值型数据按照一定的条件拆分成多列？

In R, how to split a long column of numerical data into multiple columns based on a certain criterion?

r

data-manipulation

dataframe