在 Oracle SQL 中将两个查询的结果合并为一个

Question

我有两个查询，我想在不创建函数的情况下加入它们。第一个给了我当前余额的结果。结果是 160€:

select sum(SESSIONS.PRICE) - sum(SESSIONS.AMOUNT)  as v_diff
from SESSIONS
where SESSIONS.CLIENTS_ID =:P2002_ID  
and SESSIONS.STATUS in (4,5);

第二个查询给出了额外的付款。结果是 30€:

select sum(SESSIONS.AMOUNT) as v_extra_amount
from SESSIONS
where SESSIONS.CLIENTS_ID = :P2002_ID 
and SESSIONS.STATUS = 1
and SESSIONS.PAYMENT_STATUS = 2;

所以我想问问是否可以给我 130 欧元的金额！（第一个 160 欧元 - 第二个 30 欧元）。

Answer 1

只使用条件聚合：

select (sum(case when s.STATUS in (4, 5) then s.PRICE else 0 end) - 
        sum(case when s.STATUS in (4, 5) then s.AMOUNT else 0 end) 
       ),
       sum(case when s.STATUS = 2 then s.AMOUNT end)
into v_diff, v_extra_amount
from SESSIONS s
where s.CLIENTS_ID = :P2002_ID;

或者，如果您想要一个值，只需减去：

select (sum(case when s.STATUS in (4, 5) then s.PRICE else 0 end) - 
        sum(case when s.STATUS in (4, 5) then s.AMOUNT else 0 end) -
        sum(case when s.STATUS = 1 and s.PAYMENT_STATUS = 2 then s.AMOUNT end)
       )
from SESSIONS s
where s.CLIENTS_ID = :P2002_ID;

在 Oracle SQL 中将两个查询的结果合并为一个

Join the results from two queries into one in Oracle SQL

sql

oracle

oracle11g

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oracle-apex