PHP Laravel 根据条件交替推送

Question

我在 table 中有字段 most_viewed 和 top_rated

    $most_viewed_posts = Blog::where('most_viewed', 1)->orderBy('created_at', 'desc')->get();
    $top_rated_posts = Blog::where('top_rated', 1)->orderBy('created_at', 'desc')->get();
    $featured_collection = collect();
    foreach ($most_viewed_posts as $most_viewed_post)
        $featured_collection->push($most_viewed_post);
    foreach ($top_rated_posts as $top_rated_post)
        $featured_collection->push($top_rated_post);
    $featured_posts = $featured_collection->sortBy('id', SORT_NUMERIC)->reverse()->chunk(2);

我在这里想要完成的是将结果分成 2 个。因为我在下面的图片中显示它。这是一个旋转木马。块中的第一个结果应该是 most_viewed，第二个是 top_rated.

现在的问题有时是，most_viewed post 在最高评价列中。是否有可能块中的项目总是 most_view 和 top_rated？

Answer 1

你为什么要用这么复杂的方式完成它？为什么不简单：

$most_viewed_post = Blog::where('most_viewed', 1)->orderBy('created_at', 'desc')->first();
$top_rated_post = Blog::where('top_rated', 1)->orderBy('created_at', 'desc')->first();
$featured_posts = collect([$most_viewed_post, $top_rated_post]);

更新

要获得观看次数最多 + 评分最高的配对集合，您可以使用 zip() 方法 (https://laravel.com/docs/8.x/collections#method-zip):

$most_viewed_posts = Blog::where('most_viewed', 1)->orderBy('created_at', 'desc')->get();
$top_rated_posts = Blog::where('top_rated', 1)->orderBy('created_at', 'desc')->get();

$featured_collection = $most_viewed_posts->zip($top_rated_posts);

//later you can iterate them this way:
foreach($featured_collection as [$most_viewed, $top_rated]) {
    //...output
}

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