计算列表[元组]中的出现次数

Question

输入：[('Vehicle=Boat', 'Tom'), ('Vehicle=Car', 'Scott'), ('Vehicle=Car', 'Tom'), ('Vehicle=Boat', 'Tom')]

使用以下代码我可以正确地对输入进行分组，但是计算元组中出现的次数给我带来了问题：

def groupBy(seqs, idx=1): 
    
    d = dict()
    for seq in seqs:
        k = seq[idx]
        v = d.get(k,tuple()) + (seq[:idx]+seq[idx+1:]) #new dict here where mydict[i] = count.get(i,0) + 1?
        d.update({k:v})
    return d

Returns:

{'Tom': ('Vehicle=Boat', 'Vehicle=Car', 'Vehicle=Boat'), 'Scott': ('Vehicle=Car')}

这很好，但我希望输出为：

Tom  
Vehicle=Boat: 2  
Vehicle=Car: 1  

Scott 
Vehicle=Car: 1

有人能给我指出正确的方向吗？

Answer 1

您只需用手捏碎即可：

data = [('Vehicle=Boat', 'Tom'), ('Vehicle=Car', 'Scott'), ('Vehicle=Car', 'Tom'), ('Vehicle=Boat', 'Tom')]

def groupBy(seqs, idx=0): 
    d = {}
    for seq in seqs:
        k = seq[idx]
        if k not in d:
            d[k] = {}
        rest = seq[:idx] + seq[idx+1:]
        if rest not in d[k]:
            d[k][rest] = 0
        d[k][rest] += 1
    return d

print( groupBy( data, 1 ) )

输出：

{'Tom': {('Vehicle=Boat',): 2, ('Vehicle=Car',): 1}, 'Scott': {('Vehicle=Car',): 1}}

计算列表[元组]中的出现次数

Couting occurrences in list[Tuple]

python

dictionary

tuples