使用 Python 将 str 列表为 int

Question

我有一个字符串：

ip = 'MULTIPOLYGON (((1790.0 15563.0, 1791.0 15553.0, 1790.0 15551.0, 1789.0 15549.0, 1791.0 15547.0)), ((1752.0 15451.0, 1753.0 15449.0, 1762.0 15449.0, 1764.0 15451.0, 1761.0 15451.0, 1758.0 15454.0, 1756.0 15453.0)))'

我想将其转换为以下格式，但为 int;

[((1790.0 , 15563.0) , (1791.0 , 15553.0) , (1790.0 , 15551.0) , (1789.0 , 15549.0) , (1791.0 , 15547.0)) ,((1752.0 , 15451.0) , (1753.0 , 15449.0) , (1762.0 , 15449.0) , (1764.0 , 15451.0) , (1761.0 , 15451.0) , (1758.0 , 15454.0) , (1756.0 , 15453.0))]

到目前为止我尝试了什么？

ip = 'MULTIPOLYGON (((1790.0 15563.0, 1791.0 15553.0, 1790.0 15551.0, 1789.0 15549.0, 1791.0 15547.0)), ((1752.0 15451.0, 1753.0 15449.0, 1762.0 15449.0, 1764.0 15451.0, 1761.0 15451.0, 1758.0 15454.0, 1756.0 15453.0)))'

st = ip[15:-2]
#s = st.split(',')
x = st.replace(", ", ") (")
res=[x.replace(" ", " , ")]
list(map(int, res))

这会将上述格式转换为字符串而不是整数。我收到以下错误：ValueError: invalid literal for int() with base 10: 我该如何解决？

Answer 1

试试正则表达式

import re

ip = 'MULTIPOLYGON (((1790.0 15563.0, 1791.0 15553.0, 1790.0 15551.0, 1789.0 15549.0, 1791.0 15547.0)), ((1752.0 15451.0, 1753.0 15449.0, 1762.0 15449.0, 1764.0 15451.0, 1761.0 15451.0, 1758.0 15454.0, 1756.0 15453.0)))'

output = [tuple(map(lambda x: int(float(x)),i.split())) for i in re.findall(r'(\d[\d.\s]+\d)', ip)]

print(output)

[(1790, 15563), (1791, 15553), (1790, 15551), (1789, 15549), (1791, 15547), (1752, 15451), (1753, 15449), (1762, 15449), (1764, 15451), (1761, 15451), (1758, 15454), (1756, 15453)]```

Answer 2

这可能对您有帮助：

from re import compile

pattern = compile("(\d+\.\d)+ (\d+\.\d)+")
ip = 'MULTIPOLYGON (((1790.0 15563.0, 1791.0 15553.0, 1790.0 15551.0, 1789.0 15549.0, 1791.0 15547.0)), ((1752.0 15451.0, 1753.0 15449.0, 1762.0 15449.0, 1764.0 15451.0, 1761.0 15451.0, 1758.0 15454.0, 1756.0 15453.0)))'
st = ip[15:-2]
print([tuple(float(y) for y in x) for x in pattern.findall(st)])

给出结果：

[(1790.0, 15563.0), (1791.0, 15553.0), (1790.0, 15551.0), (1789.0, 15549.0), (1791.0, 15547.0), (1752.0, 15451.0), (1753.0, 15449.0), (1762.0, 15449.0), (1764.0, 15451.0), (1761.0, 15451.0), (1758.0, 15454.0), (1756.0, 15453.0)]

Answer 3

这不是很漂亮，但它会做你想做的事，而且可能比正则表达式等价物更快：

[tuple(tuple(int(float(n))
             for n in pair.split())
       for pair in t.split(', '))
 for t in ip[16:-3].split(')), ((')]

如果你有Python 3.9+，你可以用更直观的ip.removeprefix('MULTIPOLYGON (((').removesuffix(')))')替换ip[16:-3]。

使用 Python 将 str 列表为 int

List str to int using Python

python

string

integer

replace

list