如何 POST 使用 Root 改造 return JSONArray

How to POST retrofit return JSONArray with Root

我在 json 和 root/parent

之间遇到问题

网络服务

@POST("products")
Call<List<ProductResponse>> products(@Body ProductRequest productRequest);

我的响应模型

public class ProductResponse{
   private String id_prodotto;

   private String nome_prodotto;

} 我的电话回复:

  public void products(String s){
    ProductRequest productRequest = new ProductRequest();
    productRequest.setToken(s);
    Call <List<ProductResponse>> pR = 
   ApiClient.getUserService().products(productRequest);
    pR.enqueue(new Callback<List<ProductResponse>>() {
       @Override 
        public void onResponse(Call<List<ProductResponse>> call, retrofit2.Response<List<ProductResponse>> response) {
            if(response.isSuccessful()){
                productList = response.body();
                recyclerViewProdotti.setLayoutManager(new LinearLayoutManager(getContext()));
                recyclerViewProdotti.setHasFixedSize(true);
                adapterProducts = new AdapterProducts(context.getApplicationContext(),productList,tkn);
                recyclerViewProdotti.setAdapter(adapterProducts);
            }else {
                Toast.makeText(context,"Fail Products " + tkn, Toast.LENGTH_LONG).show();
            }
        }
        @Override
        public void onFailure(Call<List<ProductResponse>> call, Throwable t) {
            Log.e("PR", t.getLocalizedMessage());
        }
    }

我的回答是:

{ "id_prodotto": "1", "nome_prodotto": "一个"} { "id_prodotto": "2", "nome_prodotto": "两个"}

但需要采取这样的回应:{ products: { "id_prodotto": "1", "nome_prodotto": "one"} { "id_prodotto": "2", "nome_prodotto": "两个"}}

我需要做什么?

您可以使用 List<Object> 因为您的回复是这样的。但是您需要在 Webservice 中删除 List。

@POST("products")
Call<ProductListResponse> products(@Body ProductRequest productRequest);

接下来,您需要使用列表创建名为 ProductListResponse 的新模型 class。

public class ProductListResponse {
    @SerializedName("products")
    private List<ProductResponse> product;
}