如何从列表中删除 0.1%？

Question

我有以下列表

data = [    '0.1%',
 'hello',
 'how are you guys',
  '0.1%',
  '1%',
 '0.1%',
  '1%', ]

我试过这个：

cell = float(data.rstrip("%"))

我想删除 1% 和 0.1%

预期输出：

    data = [ 'hello','how are you guys' ]

Answer 1

给你：

new_list = [d for d in data if d not in ['0.1%', '1%']]

Answer 2

如果您想使用更通用的东西：

result = []
for i in data:
    try:
        float(i.strip('%'))
    except:
        result.append(i)

输出：

['hello', 'how are you guys']

Answer 3

这是另一种狡猾的方法！

data = ['0.1%',
    'hello',
    'how are you guys',
    '0.1%',
    '1%',
    '0.1%',
    '1%', ]

unwanted = [0, 3, 4, 5, 6,]

for ele in sorted(unwanted, reverse=True):
    del data[ele]


print(data)

如何从列表中删除 0.1%？

How to remove 0.1% from a list?

python

regex

arrays

tuples

list