即使传递的对象不为空，Sequelize Not Null 错误

Question

目前从我的 notnull 验证器收到错误，但是我正在通过一个显然具有值的新对象传递定义的变量。用户、站点和联系人都是关联，所以我不确定在我的 api 路由中是否不创建属性然后从我的 post 请求中传递它们，但是因为这是 MySql 我相信这是必需的，我肯定是错的。任何帮助或见解将不胜感激。

Api路线

    console.log(req.body);
    db.Case.create({
        caseName: req.body.caseName,
        userId: req.body.userId,
        siteId: req.body.siteId,
        contactId: req.body.contactId
    }).then((response) => {
        console.log(response);
        res.json(response)
    }).catch((err) => {
        console.log(err);
    })
})

型号

module.exports = (sequelize, DataTypes) => {
    const Case = sequelize.define('Case', {
        id: {
            type: DataTypes.INTEGER,
            primaryKey: true,
            autoIncrement: true,
        },
        caseName: {
            type: DataTypes.STRING,
            allowNull: false,

        },          
        createdAt: {
            type: DataTypes.DATE
        },
        updatedAt: {
            type: DataTypes.DATE,
        }, 
  
    })
    Case.associate = (models) => {
        Case.belongsTo(models.User, {
            foreignKey : {
                allowNull : false
            }
        })
        Case.belongsTo(models.Site, {
            foreignKey: {
                allowNull: false
            }
        })
        Case.belongsTo(models.Contact, {
            foreignKey: {
                allowNull : false
            }
        })
    }
    return Case;
}

post请求

    const caseName = $('#caseName');
    const UserId = sessionStorage.getItem('id');
    const SiteId = $('#insertSite').attr('id');
    const ContactId = $('#insertContact').attr('id');
    
    

    if(!caseName.val().trim() || !UserId || !SiteId || !ContactId){
        console.log('Please enter all of the Case information')
        return;
    }

    const newCase = {
        caseName: caseName.val().trim(),
        UserId: UserId,
        SiteId: SiteId,
        ContactId: ContactId,
    };
    console.log(newCase);
    axios.post('/api/Case', newCase).then((res) => {
        console.log('New Case has been added' + res);

    }).catch((err) => {
        console.log(err);
    });

正在传递的测试对象

{
  caseName: 'tttttttttt',
  UserId: '1',
  SiteId: 'insertSite',
  ContactId: 'insertContact'
}

错误响应

errors: [
    ValidationErrorItem {
      message: 'Case.UserId cannot be null',
      type: 'notNull Violation',
      path: 'UserId',
      value: null,
      origin: 'CORE',
      instance: [Case],
      validatorKey: 'is_null',
      validatorName: null,
      validatorArgs: []
    },
    ValidationErrorItem {
      message: 'Case.SiteId cannot be null',
      type: 'notNull Violation',
      path: 'SiteId',
      value: null,
      origin: 'CORE',
      instance: [Case],
      validatorKey: 'is_null',
      validatorName: null,
      validatorArgs: []
    },
    ValidationErrorItem {
      message: 'Case.ContactId cannot be null',
      type: 'notNull Violation',
      path: 'ContactId',
      value: null,
      origin: 'CORE',
      instance: [Case],
      validatorKey: 'is_null',
      validatorName: null,
      validatorArgs: []
    }
  ]
}

Answer 1

您的 API create 方法中的属性大小写不正确。

caseName: req.body.caseName,
userId: req.body.userId,
siteId: req.body.siteId,
contactId: req.body.contactId

: 的两边，因为 3 个外键需要固定大小写。

即使传递的对象不为空，Sequelize Not Null 错误

Sequelize Not Null Error even though the object being passed isnt null

javascript

mysql

express

sequelize.js