SQL 找到 table 有 diag_code 填充,然后在 lookup_table 中查找
SQL to find which table has diag_code filled, and then look it up in lookup_table
我有一个查询,diag_code 要么在一个 table (UM_SERVICE) 中,要么在另一个 (LOS) 中,但我不能同时加入两个 tables 得到 diag_code 这不是空的,我能想到的。这对于查找 diag_code 是否在 table 之一和查找 table 中是否合适?可能 LOS 和 UM_SERVICE 在不同的行上都有诊断代码,它们可能不同,并且两者或其中之一可能在查找 table 中。我在 Internet 搜索中没有看到任何内容。
这是一个简化的存储过程:
SELECT distinct
c.id
,uc.id
,c.person_id
FROM dbo.CASES c
INNER JOIN dbo.UM_CASE uc with (NOLOCK) ON uc.case_id = c.id
LEFT JOIN dbo.UM_SERVICE sv (NOLOCK) ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT usc on usc.service_id = sv.id
LEFT JOIN dbo.LOS S WITH (NOLOCK) ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION SC WITH (NOLOCK) ON SC.los_id = S.id
INNER JOIN dbo.PERSON op with (NOLOCK) on op.id = c.Person_id
WHERE
(sv.diag_code is not null and c.case_id = sv.case_id
or
s.diag_code is not null and c.case_id = s.case_id)
and
(sv.diag_code is not null and sv.diag_code in (select diag_code from TABLE_LOOKUP)
or
s.diag_code is not null and s.diag_code in (select diag_code from TABLE_LOOKUP)
Table setups like this:
CASES
id person_id
UM_CASE
case_id
LOS
case_id id
LOS_EXTENSION
los_id
Person
id cid
UM_SERVICE
case_id diag_code
UM_SERVICE_CERT
service_id id
TABLE_LOOKUP
diag_code
由于您有两个不同的搜索 运行,通过单独编写搜索然后使用 [=11= 将两个结果集放在一起,write/read 会容易得多] 操作员。 UNION
将消除两个结果集中的重复项,其方式与您使用 SELECT DISTINCT
对单个结果集所做的类似。
像这样:
/*first part of union performs seach using filter on dbo.UM_SERVICE*/
SELECT
c.id
,uc.id
,c.person_id
FROM
dbo.CASES AS c
INNER JOIN dbo.UM_CASE AS uc ON uc.case_id=c.id
LEFT JOIN dbo.UM_SERVICE AS sv ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT AS usc on usc.service_id=sv.id
LEFT JOIN dbo.LOS AS S ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION AS SC ON SC.los_id= S.id
INNER JOIN dbo.PERSON AS op on op.id=c.Person_id
WHERE
sv.diag_code in (select diag_code from TABLE_LOOKUP) /*will eliminate null values in sv.diag_code*/
UNION /*deduplicate result sets*/
/*second part of union performs search using filter on dbo.LOS*/
SELECT
c.id
,uc.id
,c.person_id
FROM
dbo.CASES AS c
INNER JOIN dbo.UM_CASE AS uc ON uc.case_id=c.id
LEFT JOIN dbo.UM_SERVICE AS sv ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT AS usc on usc.service_id=sv.id
LEFT JOIN dbo.LOS AS S ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION AS SC ON SC.los_id= S.id
INNER JOIN dbo.PERSON AS op on op.id=c.Person_id
WHERE
s.diag_code in (select diag_code from TABLE_LOOKUP); /*will eliminate null values in s.diag_code*/
我有一个查询,diag_code 要么在一个 table (UM_SERVICE) 中,要么在另一个 (LOS) 中,但我不能同时加入两个 tables 得到 diag_code 这不是空的,我能想到的。这对于查找 diag_code 是否在 table 之一和查找 table 中是否合适?可能 LOS 和 UM_SERVICE 在不同的行上都有诊断代码,它们可能不同,并且两者或其中之一可能在查找 table 中。我在 Internet 搜索中没有看到任何内容。
这是一个简化的存储过程:
SELECT distinct
c.id
,uc.id
,c.person_id
FROM dbo.CASES c
INNER JOIN dbo.UM_CASE uc with (NOLOCK) ON uc.case_id = c.id
LEFT JOIN dbo.UM_SERVICE sv (NOLOCK) ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT usc on usc.service_id = sv.id
LEFT JOIN dbo.LOS S WITH (NOLOCK) ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION SC WITH (NOLOCK) ON SC.los_id = S.id
INNER JOIN dbo.PERSON op with (NOLOCK) on op.id = c.Person_id
WHERE
(sv.diag_code is not null and c.case_id = sv.case_id
or
s.diag_code is not null and c.case_id = s.case_id)
and
(sv.diag_code is not null and sv.diag_code in (select diag_code from TABLE_LOOKUP)
or
s.diag_code is not null and s.diag_code in (select diag_code from TABLE_LOOKUP)
Table setups like this:
CASES
id person_id
UM_CASE
case_id
LOS
case_id id
LOS_EXTENSION
los_id
Person
id cid
UM_SERVICE
case_id diag_code
UM_SERVICE_CERT
service_id id
TABLE_LOOKUP
diag_code
由于您有两个不同的搜索 运行,通过单独编写搜索然后使用 [=11= 将两个结果集放在一起,write/read 会容易得多] 操作员。 UNION
将消除两个结果集中的重复项,其方式与您使用 SELECT DISTINCT
对单个结果集所做的类似。
像这样:
/*first part of union performs seach using filter on dbo.UM_SERVICE*/
SELECT
c.id
,uc.id
,c.person_id
FROM
dbo.CASES AS c
INNER JOIN dbo.UM_CASE AS uc ON uc.case_id=c.id
LEFT JOIN dbo.UM_SERVICE AS sv ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT AS usc on usc.service_id=sv.id
LEFT JOIN dbo.LOS AS S ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION AS SC ON SC.los_id= S.id
INNER JOIN dbo.PERSON AS op on op.id=c.Person_id
WHERE
sv.diag_code in (select diag_code from TABLE_LOOKUP) /*will eliminate null values in sv.diag_code*/
UNION /*deduplicate result sets*/
/*second part of union performs search using filter on dbo.LOS*/
SELECT
c.id
,uc.id
,c.person_id
FROM
dbo.CASES AS c
INNER JOIN dbo.UM_CASE AS uc ON uc.case_id=c.id
LEFT JOIN dbo.UM_SERVICE AS sv ON sv.case_id = omc.case_id
LEFT JOIN dbo.UM_SERVICE_CERT AS usc on usc.service_id=sv.id
LEFT JOIN dbo.LOS AS S ON S.case_id = UC.case_id
LEFT JOIN dbo.LOS_EXTENSION AS SC ON SC.los_id= S.id
INNER JOIN dbo.PERSON AS op on op.id=c.Person_id
WHERE
s.diag_code in (select diag_code from TABLE_LOOKUP); /*will eliminate null values in s.diag_code*/