如何仅在满足另一个条件时按列过滤查询

Question

我有一个问题：

query = Usage.query.filter_by(site_id=self.site_id, invoice_num=self.invoice_num, supply_charge=self.supply_charge)

并想按日期过滤：

.filter(Usage.start_date>four_months_ago)

仅当被过滤的行具有相同的值时：

if subtotal == self.subtotal

有没有比 for 循环更好的方法？看起来效率很低

for row in query.all():
    if self.start_date > four_months_ago:
        if row.subtotal != self.subtotal:
            del row

Answer 1

条件

(subtotal == self.subtotal) & (Usage.start_date > four_months_ago)

看起来像

WHERE start_date > 'val1' AND subtotal = val2

否则，OR subtotal != val2。你可以尝试使用or_ + and_。举个例子：

subtotal = 1
for user in Usage.query.filter(
    Usage.site_id == 2,
    Usage.invoice_num == 3,
    Usage.supply_charge == 4,
    or_(
        and_(Usage.start_date > for_month_ago, Usage.subtotal == subtotal),
        Usage.subtotal != subtotal,
    )
):
    print(user)

如何仅在满足另一个条件时按列过滤查询

How to filter a query by columns only if another condition is met

python

sql

sqlalchemy