mysql 基于约束的年龄明智计数

Question

我有一个table如下

pid	patient_name	年龄	性别	dm	htn	ckd
1	一个	10	米	1	0	1
2	两个	15	米	1	1	1
3	三个	30	米	1	0	1
4	四个	40	f	1	0	1
5	五个	50	f	1	0	1
6	六个	60	f	1	0	1
7	七个	70	米	1	0	1

我需要男性患者的输出计数如下

范围	dm_count	htn_count	ckd_count
80+	0	0	0
20-29	0	0	0
50-59	0	0	0
20 岁以下	2	1	2
30-39	1	0	1
40-49	0	0	0
70-79	1	0	1
60-69	0	0	0

下面我提到了我使用的查询

select t.ranges, count(*) as occurences from (
                            select age,
                               case when age >= '0' and age < '20' then "under 20"
                               when age >= '20' and age < '30' then "20-29"
                               when age >= '30' and age < '40' then "30-39"
                               when age >= '40' and age < '50' then "40-49"
                               when age >= '50' and age < '60' then "50-59"
                               when age >= '60' and age < '70' then "60-69"
                               when age >= '70' and age < '80' then "70-79"
                               else "80+" end as ranges,sex
                               from patient_sample where sex='M') as t
                            group by t.ranges

提前致谢。

Answer 1

我假设您的问题是“如何为 dm、htn 和 ckd 添加计数列？

Select 在内部查询中对它们使用 SUM 而不是在外部查询中使用 COUNT

select 
  t.ranges, 
  count(*) as occurences, 
  sum(htn) as htn_count 
  ...
from (
  select 
     htn,
     ...
     case when age >= '0' and age < '20' then "under 20"

以相同的模式添加其他人

Answer 2

FWIW，我可能会做这样的事情...

 SELECT FLOOR(age/10)*10 range_start
      , SUM(dm) dm_count
      , SUM(htn) htn_count 
      , SUM(ckd) ckd_count 
   FROM datable 
  WHERE sex = 'm' 
  GROUP 
     BY FLOOR(age/10)*10;
+-------------+----------+-----------+-----------+
| range_start | dm_count | htn_count | ckd_count |
+-------------+----------+-----------+-----------+
|          10 |        2 |         1 |         2 |
|          30 |        1 |         0 |         1 |
|          70 |        1 |         0 |         1 |
+-------------+----------+-----------+-----------+

...并解决应用程序代码中问题的任何剩余方面

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