Svelte:如何从文件中导入所有商店而不列出所有商店?
Svelte: How to import all stores from a file without listing them all?
是否可以在一行中从一个文件中导入所有导出的商店?而不是像这样列出它们:
import { store1, store2, store3 } from './stores.js';
有没有办法做这样的事情:
import { * } from './stores.js';
或者有其他解决方法吗?
如果不是,推荐的架构是什么来避免这种需要?
不知道能不能满足您的需求,您可以导出一个对象中的所有店铺
//main.svelte
<script>
import stores from './stores.js';
let count_value, store1_v, store2_v;
stores.count.subscribe(value => {
count_value = value;
});
stores.store1.subscribe(value => {
store1_v = value;
});
stores.store2.subscribe(value => {
store2_v = value;
});
</script>
<h1>The count is {count_value}</h1>
<h1>The count is {store1_v}</h1>
<h1>The count is {store2_v}</h1>
//stores.js
import { writable } from 'svelte/store';
export const count = writable(0);
export const store1 = writable(4565465);
export const store2 = writable(345);
export default {
count,
store1,
store2,
}
商店的另一种选择是
//stores.js
import { writable } from 'svelte/store';
export default {
count: writable(0),
store1: writable(4565465),
store2: writable(345),
}
是否可以在一行中从一个文件中导入所有导出的商店?而不是像这样列出它们:
import { store1, store2, store3 } from './stores.js';
有没有办法做这样的事情:
import { * } from './stores.js';
或者有其他解决方法吗? 如果不是,推荐的架构是什么来避免这种需要?
不知道能不能满足您的需求,您可以导出一个对象中的所有店铺
//main.svelte
<script>
import stores from './stores.js';
let count_value, store1_v, store2_v;
stores.count.subscribe(value => {
count_value = value;
});
stores.store1.subscribe(value => {
store1_v = value;
});
stores.store2.subscribe(value => {
store2_v = value;
});
</script>
<h1>The count is {count_value}</h1>
<h1>The count is {store1_v}</h1>
<h1>The count is {store2_v}</h1>
//stores.js
import { writable } from 'svelte/store';
export const count = writable(0);
export const store1 = writable(4565465);
export const store2 = writable(345);
export default {
count,
store1,
store2,
}
商店的另一种选择是
//stores.js
import { writable } from 'svelte/store';
export default {
count: writable(0),
store1: writable(4565465),
store2: writable(345),
}