将变量和函数（具有不同参数）传递给函数

Question

我有一个外部函数 external_function 作为参数 x、y、step 和另一个函数 func 作为参数 x、y 和（通常但不总是）其他变量。我不知道如何传递这些附加参数。

我试过 *args 或 functools.partial，但没有成功。可能是我没用对吧

这是一个代表我真实代码问题的例子：

def general_operation(x, y, step, func):
    """
    func is a function which expects at least x & y as arguments,
    but it can expect more arguments.
    """
    number_of_iterations = int((y - x) / step)
    solutions = []
    for i in range(number_of_iterations):
        solutions.append(func(x, y))
    return solutions

def funza(x, y):
    return x + y

def gunza(x, y, additional):
    if additional == 0:
        return x + y
    elif additional == 1:
        return x - y
    elif additional == 2:
        return x * y
    elif additional == 3:
        return x / y

x = 0
y = 100

step = 0.01

# works
solutions_1 = general_operation(x, y, step, funza)

# do not know how to pass "additional" argument here
solutions_2 = general_operation(x, y, gunza)

# do not know how to pass "additional" argument here
solutions_3 = general_operation(x, y, step, gunza)

print(solutions_1)
print(solutions_2)
print(solutions_3)

Answer 1

您可以使用 *args 和 **kwargs:

def general_operation(x, y, step, func, *args, **kwargs):
    """
    A function which expects at least x & y as arguments,
    but it can expect more arguments.
    """
    number_of_iterations = int((y - x) / step)
    solutions = []
    for i in range(number_of_iterations):
        solutions.append(func(x, y, *args, **kwargs))
    return solutions

此处 *args 将包含元组中的所有未命名参数，**kwargs 将包含字典中的所有命名参数。

您可以这样调用它：

solutions_1 = general_operation(x, y, step, funza)

solutions_2 = general_operation(x, y, step, gunza, 1)

func 之外的所有其他参数都将传递给 func

将变量和函数（具有不同参数）传递给函数

Passing variables and a function (with different arguments) to a function

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arguments

function