Python，在另一个文件中处理文件运行引起的异常？

Question

我正在制作一个运行另一个文件 (B) 的 python 程序 (A)。如果 B 以代码 0 退出，则 A 也退出。但是，如果 B 崩溃了，我想在 A 中自己处理那个异常。

父/主文件(A)出现异常 that asks the same thing, however, the one asking only needs the exit code or the error message printed to stderr. However, i want the raw data otherwise provided by sys.exc_info

Answer 1

使用 check=True 选项尝试 subprocess：

来自subprocess docs：

If check is true, and the process exits with a non-zero exit code, a 
CalledProcessError exception will be raised. Attributes of that 
exception hold the arguments, the exit code, and stdout and stderr if 
they were captured.

如果 B.py 类似于：

print("HELLO from B")
raise Exception("MEH")

那么 A.py 可能是这样的：

import subprocess

try:
    print("TRYING B.py")
    subprocess.run(["python", "B.py"], check=True)
except subprocess.CalledProcessError as cpe:
    print("OH WELL: Handling exception from B.py")
    print(f"Exception from B: {cpe}")

结果：

~ > python A.py
TRYING B.py
HELLO from B
Traceback (most recent call last):
  File "B.py", line 2, in <module>
    raise Exception("MEH")
Exception: MEH
OH WELL: Handling exception from B.py
Exception from B: Command '['python', 'B.py']' returned non-zero exit status 1.

要使异常不显示，请将 B.py 更改为以下内容：

import os
import sys
sys.stderr = open(os.devnull, 'w')
print("HELLO from B")
raise Exception("MEH")

结果：

~ > python A.py
TRYING B.py
HELLO from B
OH WELL: Handling exception from B.py
Exception from B: Command '['python', 'B.py']' returned non-zero exit status 1.

Python，在另一个文件中处理文件运行引起的异常？

Python, handle exceptions caused by file ran by other file in the other file?

python

exception