React Native:控制台错误找不到变量:任务(使用 Firebase 上传和存储图像)
React Native: Console Error Can't find variable: task (Image upload and store with Firebase)
我关注了一个 tutorial on uploading photos to Firebase storage using react-native,虽然它已经超过一年了,我不得不做一些小的改变,但我相信它应该仍然有效(例如 showImagePicker 不再存在,所以我更换了它与 launchImageLibrary).
这是我的 UploadScreen.js 文件:
import * as React from 'react';
import {useState} from 'react';
import {
View,
SafeAreaView,
Text,
TouchableOpacity,
StyleSheet,
Platform,
Alert,
Image,
} from 'react-native';
import * as ImagePicker from 'react-native-image-picker';
import storage from '@react-native-firebase/storage';
import * as Progress from 'react-native-progress';
export default function UploadScreen() {
const [image, setImage] = useState('');
const [uploading, setUploading] = useState(false);
const [transferred, setTransferred] = useState(0);
const selectImage = () => {
const options = {
maxWidth: 2000,
maxHeight: 2000,
storageOptions: {
skipBackup: true,
path: 'images',
},
};
ImagePicker.launchImageLibrary(options, response => {
if (response.didCancel) {
console.log('User cancelled image picker');
} else if (response.error) {
console.log('ImagePicker Error: ', response.error);
} else if (response.customButton) {
console.log('User tapped custom button: ', response.customButton);
} else {
const source = {uri: response?.uri};
console.log(source);
setImage(source);
}
});
};
const uploadImage = async () => {
const {uri} = image;
if (uri) {
const filename = uri.substring(uri.lastIndexOf('/') + 1);
const uploadUri =
Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
setUploading(true);
setTransferred(0);
const task = storage().ref(filename).putFile(uploadUri);
// set progress state
task.on('state_changed', snapshot => {
setTransferred(
Math.round(snapshot.bytesTransferred / snapshot.totalBytes) * 10000,
);
});
}
try {
await task;
} catch (e) {
console.error(e);
}
setUploading(false);
Alert.alert(
'Photo uploaded!',
'Your photo has been uploaded to Firebase Cloud Storage!',
);
setImage('');
};
return (
<SafeAreaView style={styles.container}>
<TouchableOpacity style={styles.selectButton} onPress={selectImage}>
<Text style={styles.buttonText}>Pick an image</Text>
</TouchableOpacity>
<View style={styles.imageContainer}>
{image !== '' && image !== undefined && (
<Image source={{uri: image?.uri}} style={styles.imageBox} />
)}
{uploading ? (
<View style={styles.progressBarContainer}>
<Progress.Bar progress={transferred} width={300} />
</View>
) : (
<TouchableOpacity style={styles.uploadButton} onPress={uploadImage}>
<Text style={styles.buttonText}>Upload image</Text>
</TouchableOpacity>
)}
</View>
</SafeAreaView>
);
}
const styles = StyleSheet.create({
container: {
flex: 1,
alignItems: 'center',
backgroundColor: '#bbded6',
},
selectButton: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#8ac6d1',
alignItems: 'center',
justifyContent: 'center',
},
selectButton2: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#8ac6d1',
alignItems: 'center',
justifyContent: 'center',
marginTop: 20,
},
uploadButton: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#ffb6b9',
alignItems: 'center',
justifyContent: 'center',
marginTop: 20,
},
buttonText: {
color: 'white',
fontSize: 18,
fontWeight: 'bold',
},
imageContainer: {
marginTop: 30,
marginBottom: 50,
alignItems: 'center',
},
progressBarContainer: {
marginTop: 20,
},
imageBox: {
width: 300,
height: 300,
},
});
当我 运行 在我的 phone 上将其作为 ios 应用程序时,按下“上传文件”按钮后出现此错误:
这似乎与此处的代码有关...
我不太确定从这里开始做什么,因为我对 React Native 还很陌生,所以如果您能就错误的含义以及如何修复它提供任何帮助,我们将不胜感激!谢谢。
您将 task
定义为 uploadImage
中第一个块的局部常量,这意味着第二个块中的代码无法找到它。
为了解决这个问题,我将 task
拉到函数级变量中:
const uploadImage = async () => {
const {uri} = image;
let task; // Add this
if (uri) {
const filename = uri.substring(uri.lastIndexOf('/') + 1);
const uploadUri =
Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
setUploading(true);
setTransferred(0);
task = storage().ref(filename).putFile(uploadUri); // Remove const here
// set progress state
task.on('state_changed', snapshot => {
setTransferred(
Math.round(snapshot.bytesTransferred / snapshot.totalBytes) * 10000,
);
});
}
try {
await task;
} catch (e) {
console.error(e);
}
我关注了一个 tutorial on uploading photos to Firebase storage using react-native,虽然它已经超过一年了,我不得不做一些小的改变,但我相信它应该仍然有效(例如 showImagePicker 不再存在,所以我更换了它与 launchImageLibrary).
这是我的 UploadScreen.js 文件:
import * as React from 'react';
import {useState} from 'react';
import {
View,
SafeAreaView,
Text,
TouchableOpacity,
StyleSheet,
Platform,
Alert,
Image,
} from 'react-native';
import * as ImagePicker from 'react-native-image-picker';
import storage from '@react-native-firebase/storage';
import * as Progress from 'react-native-progress';
export default function UploadScreen() {
const [image, setImage] = useState('');
const [uploading, setUploading] = useState(false);
const [transferred, setTransferred] = useState(0);
const selectImage = () => {
const options = {
maxWidth: 2000,
maxHeight: 2000,
storageOptions: {
skipBackup: true,
path: 'images',
},
};
ImagePicker.launchImageLibrary(options, response => {
if (response.didCancel) {
console.log('User cancelled image picker');
} else if (response.error) {
console.log('ImagePicker Error: ', response.error);
} else if (response.customButton) {
console.log('User tapped custom button: ', response.customButton);
} else {
const source = {uri: response?.uri};
console.log(source);
setImage(source);
}
});
};
const uploadImage = async () => {
const {uri} = image;
if (uri) {
const filename = uri.substring(uri.lastIndexOf('/') + 1);
const uploadUri =
Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
setUploading(true);
setTransferred(0);
const task = storage().ref(filename).putFile(uploadUri);
// set progress state
task.on('state_changed', snapshot => {
setTransferred(
Math.round(snapshot.bytesTransferred / snapshot.totalBytes) * 10000,
);
});
}
try {
await task;
} catch (e) {
console.error(e);
}
setUploading(false);
Alert.alert(
'Photo uploaded!',
'Your photo has been uploaded to Firebase Cloud Storage!',
);
setImage('');
};
return (
<SafeAreaView style={styles.container}>
<TouchableOpacity style={styles.selectButton} onPress={selectImage}>
<Text style={styles.buttonText}>Pick an image</Text>
</TouchableOpacity>
<View style={styles.imageContainer}>
{image !== '' && image !== undefined && (
<Image source={{uri: image?.uri}} style={styles.imageBox} />
)}
{uploading ? (
<View style={styles.progressBarContainer}>
<Progress.Bar progress={transferred} width={300} />
</View>
) : (
<TouchableOpacity style={styles.uploadButton} onPress={uploadImage}>
<Text style={styles.buttonText}>Upload image</Text>
</TouchableOpacity>
)}
</View>
</SafeAreaView>
);
}
const styles = StyleSheet.create({
container: {
flex: 1,
alignItems: 'center',
backgroundColor: '#bbded6',
},
selectButton: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#8ac6d1',
alignItems: 'center',
justifyContent: 'center',
},
selectButton2: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#8ac6d1',
alignItems: 'center',
justifyContent: 'center',
marginTop: 20,
},
uploadButton: {
borderRadius: 5,
width: 150,
height: 50,
backgroundColor: '#ffb6b9',
alignItems: 'center',
justifyContent: 'center',
marginTop: 20,
},
buttonText: {
color: 'white',
fontSize: 18,
fontWeight: 'bold',
},
imageContainer: {
marginTop: 30,
marginBottom: 50,
alignItems: 'center',
},
progressBarContainer: {
marginTop: 20,
},
imageBox: {
width: 300,
height: 300,
},
});
当我 运行 在我的 phone 上将其作为 ios 应用程序时,按下“上传文件”按钮后出现此错误:
这似乎与此处的代码有关...
我不太确定从这里开始做什么,因为我对 React Native 还很陌生,所以如果您能就错误的含义以及如何修复它提供任何帮助,我们将不胜感激!谢谢。
您将 task
定义为 uploadImage
中第一个块的局部常量,这意味着第二个块中的代码无法找到它。
为了解决这个问题,我将 task
拉到函数级变量中:
const uploadImage = async () => {
const {uri} = image;
let task; // Add this
if (uri) {
const filename = uri.substring(uri.lastIndexOf('/') + 1);
const uploadUri =
Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
setUploading(true);
setTransferred(0);
task = storage().ref(filename).putFile(uploadUri); // Remove const here
// set progress state
task.on('state_changed', snapshot => {
setTransferred(
Math.round(snapshot.bytesTransferred / snapshot.totalBytes) * 10000,
);
});
}
try {
await task;
} catch (e) {
console.error(e);
}