检索满足某些条件的字典

Question

我有一个字典，如下所示：

x = {
   "Student": [
       {
        "tags": {
                    "name": "Alex",
                    "class": "Biology",
                    "gender": "male",
                         },
        "Nationality": "",
        "Test Score": 10.0,
        "Exam Score": 70.0,
                
        },
{
        "tags": {
                    "id": "A123",
                    "height": "170",
                    "age": "15",
                         },
        "Nationality": "",
        "Test Score": 20.0,
        "Exam Score": 80.0,
                
        },
              ],
    }

我想获得上面数据模式的考试成绩和考试成绩，其中有一个嵌套字典，键 'tag' 键为“id”、“height”和“age”

所以期望值应该是“考试成绩”=20.0 和“考试成绩”=80.0

我已经尝试了下面的实现，但它似乎只检查 'Student' 列表中的第一个值（长度为 2），但我需要它来检查列表中的所有项目（在这种情况下有两个项目）。

search_tag = ["id", "height", "age"]
    val_list = []

    if all([t in search_tag for t in x["Student"][0]["tags"].keys()]):
        val_list.append(x["Student"][0]["Test Score"])
        val_list.append(x["Student"][0]["Exam Score"])

Answer 1

您只需要遍历 "Student":

索引的列表

x = {
   "Student": [
       {
        "tags": {
                    "name": "Alex",
                    "class": "Biology",
                    "gender": "male",
                         },
        "Nationality": "",
        "Test Score": 10.0,
        "Exam Score": 70.0,
                
        },
       {
        "tags": {
                    "id": "A123",
                    "height": "170",
                    "age": "15",
                         },
        "Nationality": "",
        "Test Score": 20.0,
        "Exam Score": 80.0,
                
        },
    ],
  }

search_tag = ["id", "height", "age"]

val_list = []
for item in x["Student"]:
    if all(t in search_tag for t in item['tags']):
        val_list.append(item["Test Score"])
        val_list.append(item["Exam Score"])
print(val_list)

输出：

[20.0, 80.0]

Answer 2

您可以将 set 个密钥与 .keys() 进行比较：

x = {
    "Student": [
        {
            "tags": {
                "name": "Alex",
                "class": "Biology",
                "gender": "male",
            },
            "Nationality": "",
            "Test Score": 10.0,
            "Exam Score": 70.0,
        },
        {
            "tags": {
                "id": "A123",
                "height": "170",
                "age": "15",
            },
            "Nationality": "",
            "Test Score": 20.0,
            "Exam Score": 80.0,
        },
    ],
}

to_search = {"age", "id", "height"}

for student in x["Student"]:
    if student["tags"].keys() == to_search:
        print(student["Test Score"])
        print(student["Exam Score"])

打印：

20.0
80.0

Answer 3

x = {'Student': [{'Exam Score': 70.0,
              'Nationality': '',
              'Test Score': 10.0,
              'tags': {'class': 'Biology', 'gender': 'male', 'name': 'Alex'}},
             {'Exam Score': 80.0,
              'Nationality': '',
              'Test Score': 20.0,
              'tags': {'age': '15', 'height': '170', 'id': 'A123'}}]}

search_tag = {"age", "height", "id"}
for student in x["Student"]:
    if search_tag.issubset(student["tags"]):
        print([student["Test Score"], student["Exam Score"]])

使用集合检查条件。

这会打印

[20.0, 80.0]

检索满足某些条件的字典

Retrieve dictionary which satisfies some condition

python

dictionary

list

data-science