如何编写将 returns class 类型指定为参数的 C# 函数？

Question

我正在尝试为 C# MVC 应用程序编写一个 JSON 帮助程序 class，该应用程序 returns 一个被指定为参数的类型的 class 实例。这样做的目的是简化将 JSON 反序列化为正确类型的模型。不幸的是，我运行陷入了一个错误：

'ModelType' is a variable but used as a type.

这是我使用的代码：


        public ActionResult api_call() {
            // Parse/Map request stream containing a JSON to a C# object
            json_helper _o_json_helper = new json_helper();
            pollread_read_request _request = _o_json_helper.parse_json_to_object(Assembly.GetExecutingAssembly().GetType("pollread_read_request"), Request.InputStream); 
            // Create a business logic instance
            Pollmaker_business_logic _business_logic = new Pollmaker_business_logic();
            // process request using business logic
            List<pollread_read_response> _response = _business_logic.api_call(_request);
            // return result
            return Json(_response, JsonRequestBehavior.AllowGet);
        }

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Reflection;
namespace Umbrella.Abstracts {
    public class json_helper {
        public Object parse_json_to_object(Type ClassModelType, System.IO.Stream InputStream) {
            object _result = Activator.CreateInstance(ClassModelType);
            try {
                string _json_request = "";
                using (System.IO.Stream _oRequestStream = InputStream) {
                    _oRequestStream.Seek(0, System.IO.SeekOrigin.Begin);
                    _json_request = new System.IO.StreamReader(_oRequestStream).ReadToEnd();
                }
                if (!String.IsNullOrEmpty(_json_request)) {
                    _result = Newtonsoft.Json.JsonConvert.DeserializeObject<ClassModelType> (_json_request);
                }
            } catch { }
            return _result;               
        }
        public json_helper() {}
    }
}

Answer 1

您是否也尝试过只发送程序集名称和类型名称？

object _result = Activator.CreateInstance(ClassModelType.Assembly.FullName, ClassModelType.Name);

Answer 2

使用 DeserializeObject 的非泛型重载。

_result = Newtonsoft.Json.JsonConvert.DeserializeObject(_json_request, ClassModelType);

如何编写将 returns class 类型指定为参数的 C# 函数？

How to write a C# Function that returns a class type speficifed as a parameter?

c#

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class

function