Django 表单初始化方法失败
Django form init method failing
我有一个用户添加表单视图,它要求提供信息并将新用户保存到数据库中。当我尝试保存新的用户记录时,出现以下错误。
TypeError at /user/add/
__init__() missing 1 required positional argument: 'customer'
Request Method: GET
Request URL: http://localhost:8000/user/add/
Django Version: 3.0.5
Exception Type: TypeError
Exception Value:
__init__() missing 1 required positional argument: 'customer'
Exception Location: D:\Job Documents\DDS\AuthenticationProject\env\lib\site-packages\django\views\generic\edit.py in get_form, line 33
Python Executable: D:\Job Documents\DDS\AuthenticationProject\env\Scripts\python.exe
Python Version: 3.9.0
Python Path:
['D:\Job Documents\DDS\AuthenticationProject\auth',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\python39.zip',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\DLLs',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\lib',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39',
'D:\Job Documents\DDS\AuthenticationProject\env',
'D:\Job Documents\DDS\AuthenticationProject\env\lib\site-packages']
Server time: Sun, 15 Aug 2021 08:05:30 +0000
我正在使用客户对象来区分用户,因此我希望表单知道它是由谁填写的,这样新创建的用户将拥有与创建者相同的客户对象。
这个错误没有准确显示我的错误在代码中的位置。相反,它在实际的 django 代码中显示了一些错误,我正在使用的是通用的东西。
class AddUserFormView(FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = "Account has been created! The user is able to log in."
def post(self, request):
form = self.form_class(customer=request.user.customer,
data=request.POST, files=request.FILES)
if form.is_valid():
user_face_img_md5 = Image.open(
request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(
request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(obj.__dict__,
user_face_img_md5,
user_head_img_md5)
print(f"Request Response [Add User] --> {response.text}")
# if response.text['status'] != 45001:
# messages.error(f'Something went wrong. {response.text}')
return redirect('add-user')
else:
messages.error(request, form.errors)
return redirect('add-user')
class TbUserAddForm(CustomUserCreationForm):
email = forms.EmailField()
user_head_img_md5 = forms.ImageField(label='Avatar', required=True)
user_face_img_md5 = forms.ImageField(
label='Face Recognition Image', required=True)
def __init__(self, customer, *args, **kwargs):
super().__init__(*args, **kwargs)
print(f'USER ADD FORM CUSTOMER -> {customer}')
self.customer = customer
if self.customer:
self.fields['role'].queryset = TbRole.objects.all().filter(
customer=self.customer)
self.fields['department'].queryset = TbDepartment.objects.all().filter(
customer=self.customer)
class Meta:
model = TbUser
fields = [...]
path('add/', views.AddUserFormView.as_view(), name='add-user'),
用户没有被 django 保存,但是 addUserApi()
向另一个服务器发送了一个请求。因此,有时会创建用户,因为 addUserApi 已经起作用。但是抛出了同样的错误。
您应该覆盖 .get_form_kwargs(…)
method [Django-doc] 以将数据传递给您在 GET 和 POST 请求中构建的表单:
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.messages.views import SuccessMessageMixin
from django.urls import reverse_lazy
class AddUserFormView(LoginRequiredMixin, SuccessMessageMixin, FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = 'Account has been created! The user is able to log in.'
success_url = reverse_lazy('add-user')
def <b>get_form_kwargs</b>(self):
formkw = super().get_form_kwargs()
formkw['customer'] = self.request.user.customer
return formkw
def form_valid(self, form):
user_face_img_md5 = Image.open(self.request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(self.request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(
obj.__dict__,
user_face_img_md5,
user_head_img_md5
)
print(f'Request Response [Add User] --> {response.text}')
return super().form_valid(form)
通常不会覆盖基于class的视图的post
and/orget
方法,因为那包含大部分样板代码。可能在这里覆盖 .form_valid(…)
method [Django-doc] 以指定在表单有效的情况下应该发生什么就足够了。
Note: You can limit views to a class-based view to authenticated users with the
LoginRequiredMixin
mixin [Django-doc].
Note: One can make use of the SuccessMessageMixin
mixin
to a view to add a success message in case the form was valid.
我有一个用户添加表单视图,它要求提供信息并将新用户保存到数据库中。当我尝试保存新的用户记录时,出现以下错误。
TypeError at /user/add/
__init__() missing 1 required positional argument: 'customer'
Request Method: GET
Request URL: http://localhost:8000/user/add/
Django Version: 3.0.5
Exception Type: TypeError
Exception Value:
__init__() missing 1 required positional argument: 'customer'
Exception Location: D:\Job Documents\DDS\AuthenticationProject\env\lib\site-packages\django\views\generic\edit.py in get_form, line 33
Python Executable: D:\Job Documents\DDS\AuthenticationProject\env\Scripts\python.exe
Python Version: 3.9.0
Python Path:
['D:\Job Documents\DDS\AuthenticationProject\auth',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\python39.zip',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\DLLs',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39\lib',
'C:\Users\bratca\AppData\Local\Programs\Python\Python39',
'D:\Job Documents\DDS\AuthenticationProject\env',
'D:\Job Documents\DDS\AuthenticationProject\env\lib\site-packages']
Server time: Sun, 15 Aug 2021 08:05:30 +0000
我正在使用客户对象来区分用户,因此我希望表单知道它是由谁填写的,这样新创建的用户将拥有与创建者相同的客户对象。
这个错误没有准确显示我的错误在代码中的位置。相反,它在实际的 django 代码中显示了一些错误,我正在使用的是通用的东西。
class AddUserFormView(FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = "Account has been created! The user is able to log in."
def post(self, request):
form = self.form_class(customer=request.user.customer,
data=request.POST, files=request.FILES)
if form.is_valid():
user_face_img_md5 = Image.open(
request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(
request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(obj.__dict__,
user_face_img_md5,
user_head_img_md5)
print(f"Request Response [Add User] --> {response.text}")
# if response.text['status'] != 45001:
# messages.error(f'Something went wrong. {response.text}')
return redirect('add-user')
else:
messages.error(request, form.errors)
return redirect('add-user')
class TbUserAddForm(CustomUserCreationForm):
email = forms.EmailField()
user_head_img_md5 = forms.ImageField(label='Avatar', required=True)
user_face_img_md5 = forms.ImageField(
label='Face Recognition Image', required=True)
def __init__(self, customer, *args, **kwargs):
super().__init__(*args, **kwargs)
print(f'USER ADD FORM CUSTOMER -> {customer}')
self.customer = customer
if self.customer:
self.fields['role'].queryset = TbRole.objects.all().filter(
customer=self.customer)
self.fields['department'].queryset = TbDepartment.objects.all().filter(
customer=self.customer)
class Meta:
model = TbUser
fields = [...]
path('add/', views.AddUserFormView.as_view(), name='add-user'),
用户没有被 django 保存,但是 addUserApi()
向另一个服务器发送了一个请求。因此,有时会创建用户,因为 addUserApi 已经起作用。但是抛出了同样的错误。
您应该覆盖 .get_form_kwargs(…)
method [Django-doc] 以将数据传递给您在 GET 和 POST 请求中构建的表单:
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.messages.views import SuccessMessageMixin
from django.urls import reverse_lazy
class AddUserFormView(LoginRequiredMixin, SuccessMessageMixin, FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = 'Account has been created! The user is able to log in.'
success_url = reverse_lazy('add-user')
def <b>get_form_kwargs</b>(self):
formkw = super().get_form_kwargs()
formkw['customer'] = self.request.user.customer
return formkw
def form_valid(self, form):
user_face_img_md5 = Image.open(self.request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(self.request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(
obj.__dict__,
user_face_img_md5,
user_head_img_md5
)
print(f'Request Response [Add User] --> {response.text}')
return super().form_valid(form)
通常不会覆盖基于class的视图的post
and/orget
方法,因为那包含大部分样板代码。可能在这里覆盖 .form_valid(…)
method [Django-doc] 以指定在表单有效的情况下应该发生什么就足够了。
Note: You can limit views to a class-based view to authenticated users with the
LoginRequiredMixin
mixin [Django-doc].
Note: One can make use of the
SuccessMessageMixin
mixin to a view to add a success message in case the form was valid.