获取列中可用数据的唯一长度，在 Oracle 中用逗号分隔

Question

需要获取列中可用数据的唯一长度，以逗号分隔。已尝试以下查询但收到错误提示

ORA-00936: missing expression 00936. 00000 - "missing expression" *Cause: *Action: Error at Line: 2 Column: 16

已使用查询

SELECT LISTAGG(
           SELECT DISTINCT LENGTH(ColumnName)
           FROM TableName
           WHERE LENGTH(ColumnName) NOT BETWEEN 6 AND 10) AS AliasName, ','
           ) within group (order by ColumnName) 
FROM DUAL;

下面的查询错误说

ORA-30482: DISTINCT option not allowed for this function 30482. 00000 - "DISTINCT option not allowed for this function" *Cause: *Action: Error at Line: 1 Column: 8

SELECT LISTAGG(DISTINCT LENGTH(ColumnName), ',')  within group (order by LENGTH(ColumnName))
FROM TableName
WHERE LENGTH(ColumnName) NOT BETWEEN 6 AND 10;

请协助我。

Answer 1

下面的查询提供了所需的结果。

SELECT listagg(AliasName, ',') within group (order by AliasName) AS NewAliasName 
FROM (
    SELECT DISTINCT LENGTH(ColumnName) AS AliasName
    FROM TableName
    WHERE LENGTH(ColumnName) NOT BETWEEN 6 AND 10
    );

我能得到比这更好的查询吗？

Answer 2

我只是想知道为什么要将值转换为单个字符串。为什么不 return 多行：

SELECT LENGTH(ColumnName)
FROM TableName
WHERE LENGTH(ColumnName) NOT BETWEEN 6 AND 10;
GROUP BY LENGTH(ColumnName) ;

这将允许您添加一个额外的列来计算具有特定长度的行数。

获取列中可用数据的唯一长度，在 Oracle 中用逗号分隔

Get unique length of data available in a column with comma separated in Oracle

sql

oracle

split

oracle11g