每天收发短信 (Python)

Question

这是我的代码：

from zeep import Client
from datetime import datetime
from threading import Timer
def send_simple_sms(txt):
    send_url = 'URL'
    client = Client(send_url)
    username = "MyUsername"
    password = "Password"
    text = txt
    to_type = client.get_type('ns0:ArrayOfString')
    to = to_type(['xxxxxxxxxxx'])
    from_ = "xxxxxxxx"
    result = client.service.SendSimpleSMS(username, password, to, from_, text, False)
    print(result)
def timer8():
    send_simple_sms('fff')
def timer9():
    send_simple_sms('sss')
def timer10():
    send_simple_sms('aaa')
def timer14():
    send_simple_sms('uuu')
def timer00():
    send_simple_sms('ppp')
td = datetime.today()
_8clock = td.replace(day=td.day+1, hour=8, minute=0, second=0, microsecond=0)
_9clock = td.replace(day=td.day+1, hour=9, minute=0, second=0, microsecond=0)
_10clock = td.replace(day=td.day+1, hour=10, minute=0, second=0, microsecond=0)
_14clock = td.replace(day=td.day+1, hour=14, minute=0, second=0, microsecond=0)
_00clock = td.replace(day=td.day+1, hour=0, minute=0, second=0, microsecond=0)
delta_8 = _8clock - td
delta_9 = _9clock - td
delta_10 = _10clock - td
delta_14 = _14clock - td
delta_00 = _00clock - td
secs8 = delta_8.seconds+1
secs9 = delta_9.seconds+1
secs10 = delta_10.seconds+1
secs14 = delta_14.seconds+1
secs00 = delta_00.seconds+1
Timer(secs8, timer8)
Timer(secs9, timer9)
Timer(secs10, timer10)
Timer(secs14, timer14)
Timer(secs00, timer00)

我想每天在这些时间收到一些东西（比如短信）： 8:0:0 9:0:0 10:0:0 14:0:0 0:0:0 我一直这样做到这里。但我有问题一起使用所有时间。你能帮助我吗？我该怎么办？

Answer 1

如果您的代码在 linux 环境中运行ning，最好的方法是使用 crontab，这样您的代码就不会总是运行ning。您将脚本配置为运行一次，然后在您想要的日期和时间使用 crontab 启动它。 Here 你可以找到关于 crontab 的最简单的信息。

每天收发短信 (Python)

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