如何在d3js中旋转立方体的角度？

Question

Can anyone give any reference how to make an exact chart in d3js

How to rotate the SVG to the opposite angle. please refer to the image for more details. the result should be like this image given. If anyone has some suggested material for this then that will be really helpful. The Code that I have given here only shows a single column and it's in opposite dirrection

<style>
    * {
        margin: 30;
        padding: 30;
        border: 0;
    }

    body {
        background: white;
    }

    .forward {
        fill: #ee5252;
    }

    .top {
        fill: #b43c3c;
    }

    .side {
        fill: #b23b3b;
    }
</style>
<script src="https://d3js.org/d3.v3.js"></script>
<svg>

</svg>

<script>
    var svg = d3.select('svg');

    var rect3d = svg.append('g')
        .attr('height', 50)
        .attr('width', 20)
        .attr("transform", "translate (15,15)")
        ;

    var rh = 130, rw = 20, ang = 45;

    rect3d.append("rect")
        .attr("class", "forward")
        .attr("x", 0)
        .attr("y", 0)
        .attr("width", rw)
        .attr("height", rh)
        ;

    rect3d.append("rect")
        .attr("class", "top")
        .attr("x", 0)
        .attr("y", 0)
        .attr("width", rw)
        .attr("height", rh / 2)
        .attr("transform", "translate (" + (-rh / 2) + "," + (-rh / 2) + ") skewX(" + 45 + ")")
        ;

  rect3d.append("rect")
    .attr("class", "side")
   .attr("x", 0)
  .attr("y", 0)
  .attr("width", rh/2)
  .attr("height", rh)
  .attr ("transform", "translate ("+(-rh/2)+","+(-rh/2)+") skewY("+ang+")")
  ;



</script>

Answer 1

这里是 X/Y 具有深度效果的轴的解决方案：

const add3DBar = (parent, xPos, yPos, width, height, depth, duration) => {
  const g = parent.append('g').attr('transform', `translate(${xPos}, ${yPos})`);
  
  g.append('path')
   .attr('d', `M 0,0 V [=10=] H ${width} V 0 H 0 Z`)
   .style('fill', '#000081')
   .transition()
   .duration(duration)
   .attr('d', `M 0,0 V ${-height} H ${width} V 0 H 0 Z`);
  
  g.append('path')
   .attr('d', `M 0,[=10=] L ${depth},${-depth} H ${depth + width} L ${width},0 Z`)
   .style('fill', '#0000FF')
   .transition()
   .duration(duration)
   .attr('d', `M 0,${-height} L ${depth},${-height-depth} H ${depth + width} L ${width},${-height} Z`);

  g.append('path')
   .attr('d', `M ${width},0 L ${width + depth},${-depth}, V ${-depth} L ${width},0 Z`)
   .style('fill', '#0000C0')
   .transition()
   .duration(duration)
   .attr('d', `M ${width},0 L ${width + depth},${-depth}, V ${-height-depth} L ${width},${-height} Z`);
}

const addXAxis = (parent, xPos, yPos, width, depth) => {
    const scale = d3.scaleBand()
    .domain(['A', 'B', 'C'])
    .range([0, width])
  const axis =  d3.axisBottom()
    .scale(scale)
  const g = parent.append('g');
  g.call(axis)
    .attr('transform', `translate(${xPos},${yPos})`)
  const path = `M 0,0 H ${width} L${width + depth} ${-depth} H ${depth} L 0,0 Z`;
  g.append('path')
    .attr('d', path)
    .style('stroke', 'none')
    .style('fill', '#ccc')
};

const addYAxis = (parent, xPos, yPos, height, depth) => {
    const scale = d3.scaleLinear()
    .domain([0, 0.3])
    .range([0, -height])
  const axis =  d3.axisLeft()
    .scale(scale)
    .ticks(4)
  const g = parent.append('g');
  g.call(axis)
    .attr('transform', `translate(${xPos},${yPos})`)
  const path = `M 0,0 V ${-height} L${depth} ${-height - depth} V ${-depth} L 0,0 Z`;
  g.append('path')
    .attr('d', path)
    .style('stroke', 'none')
    .style('fill', '#ccc')
};


const svg = d3.select('svg');

addXAxis(svg, 30, 150, 200, 10);
addYAxis(svg, 30, 150, 120, 10);

add3DBar(svg, 50, 150, 30, 100, 10, 500);
add3DBar(svg, 115, 150, 30, 70, 10, 1000);
add3DBar(svg, 180, 150, 30, 120, 10, 1500);

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/7.0.1/d3.min.js"></script>

<svg width="300" height="200"/>

如何在d3js中旋转立方体的角度？

How to rotate the angle of the cube in d3js?

javascript

node.js

d3.js