Kivy 如何访问子窗口小部件中的窗口小部件

Question

在此代码中，有一个按钮，我在主按钮内制作了一个切换按钮。在按下主按钮时，我希望切换按钮的状态为“向下”。我该怎么做？

主要代码：

from kivy.app import App
from kivy.uix.button import Button
from kivy.uix.togglebutton import ToggleButton
from kivy.uix.floatlayout import FloatLayout
from kivy.lang import Builder
from kivy.uix.widget import Widget
from kivy.uix.screenmanager import Screen,ScreenManager

class Main(Screen):
    def onbtn(self,widget):
        for child in self.ids.Fl.children:
            if isinstance(child, ToggleButton): # This part is wrong... How to access Widgets inside child Widgets?
                child.state='down'

class Manager(ScreenManager):
    pass
kv=Builder.load_file("test2.kv")
screen=Manager()
screen.add_widget(Main(name="main"))

class Test(App):
    def build(self):
        return screen

Test().run()

Kv代码：

<Main>:
    name: "main"
    FloatLayout:
        id: Fl
        Button:
            id: btn1
            text: "BTN 1"
            size_hint: (.5,.3)
            pos_hint: {"center_x":.5,"center_y":.6}
            on_press:
                root.onbtn(self)
            ToggleButton:
                id: tglbtn1 # How to Access this button to change its state to down
                size: 80,80
                text: "TGL BTN 1"
                pos: 500,400

Answer 1

只需更改：

class Main(Screen):
    def onbtn(self,widget):
        for child in self.ids.Fl.children:
            if isinstance(child, ToggleButton): # This part is wrong... How to access Widgets inside child Widgets?
                child.state='down'

至：

class Main(Screen):
    def onbtn(self,widget):
        for child in widget.children:
            if isinstance(child, ToggleButton):
                child.state='down'

传递给onbtn()方法的widget是Button.

Kivy 如何访问子窗口小部件中的窗口小部件

Kivy How to Access Widgets inside Child Widgets

python

kivy

kivy-language

kivymd