防止 Sequelize Join 返回 include table 的主键

Question

我有一个 sequelize 查询，它呈现正确的 SQL 语句，除了它将 return 加入的 table 的主键。由于此查询使用 Group By 附加字段是 unacceptable 但我不确定如何删除它。

userDB.tblUsers.belongsTo(userDB.tblSMSSent, { foreignKey: 'collector', targetKey: 'user' });
    userDB.tblSMSSent.hasMany(userDB.tblUsers);

    let users = await userDB.tblUsers.findAll({
        attributes: ['collector', 'tblUsers.id'],
        include: {
            model: userDB.tblSMSSent,
            as: 'tblSMSSent',
            attributes: [[sequelize.fn('COUNT', 'tblSMSSent.id'), 'numMessages']]
        },
        group: ['tblUsers.collector', 'tblUsers.id'],
        logging: console.log
    })

渲染出来的SQL是这样的：

SELECT 
    [tblUsers].[collector], 
    [tblUsers].[id], 
    [tblSMSSent].[id] AS [tblSMSSent.id], 
    COUNT(N'tblSMSSent.id') AS [tblSMSSent.numMessages] 
FROM [dbo].[tblUsers] AS [tblUsers] LEFT OUTER JOIN [dbo].[tblSMSSent] AS [tblSMSSent] ON [tblUsers].[collector] = [tblSMSSent].[user] 
GROUP BY [tblUsers].[collector], [tblUsers].[id];

我需要这个不包含 tblSMSSent.id 的查询。我曾尝试在包含属性中使用 exclude: tblSMSSent.id，如中所述，但也没有成功。我如何才能从我的查询中正确排除此列？

Answer 1

在发送到 sequelize 的 JSON 中添加了 raw:true 标签。这强制仅包含没有主键的必填字段。

防止 Sequelize Join 返回 include table 的主键

Prevent Sequelize Join from returning primary key of include table

node.js

sequelize.js