小时总和 nestjs

Question

在函数下面的 javascript 代码中，在数据库（使用 typerom）上执行一个 select，其中的数组格式如下：

JSON 数据示例：

{
        "id": 1,
        "nome": "prova2",
        "datacreazione": "2021-09-05T08:41:29.000Z",
        "costo": 23,
        "ore": "08:00",
        "IdPreventivo": 1,
        "IdUtente": 2
    },
    {
        "id": 2,
        "nome": "prova2",
        "datacreazione": "2021-09-06T08:38:26.000Z",
        "costo": 23,
        "ore": "08:00",
        "IdPreventivo": 1,
        "IdUtente": 2
    }

小时数 (ore) 字段包含 activity 的总小时数，我想做的是通过添加和执行所有 [=12] 的总和来计算总小时数=] 在该字段中为数组的每个元素输入时间，格式为 HH: MM，我该怎么做？

AttivitaprevService.js

@Injectable()
export class AttivitaprevService {
  constructor(
    @InjectRepository(Attivitaprev) private repo: Repository<Attivitaprev>
  ) {}

  create(dto: CreateAttivitaprevDto) {
    return this.repo.save(dto);
  }

  findAll() {
    return `This action returns all attivitaprev`;
  }

  async findOne(id: number) {
    return await this.repo.find({
      where: { IdPreventivo: id },
    });
  }

  sumofhour = (time1, time2) => {
    let [h1, m1] = time1.split(':')
    let [h2, m2] = time2.split(':')
  
    return ((+h1 + (+m1 / 60)) + (+h2 + (+m2 / 60)))
  }

  async totaleore(id: number) {
    var values= await this.repo.find({
      where: { IdPreventivo: id },
    });

    return values;
  }

..

Answer 1

您可以先将小时数转换为分钟数，然后您可以这样计算总小时数：

const data = [
  {
    "id": 1,
    "nome": "prova2",
    "datacreazione": "2021-09-05T08:41:29.000Z",
    "costo": 23,
    "ore": "08:30",
    "IdPreventivo": 1,
    "IdUtente": 2
  },
  {
    "id": 2,
    "nome": "prova2",
    "datacreazione": "2021-09-06T08:38:26.000Z",
    "costo": 23,
    "ore": "08:30",
    "IdPreventivo": 1,
    "IdUtente": 2
  }
]

function getTotalMinutes() {
   return data.reduce((acc, curr) => {
        const [hour, minutes ] = curr.ore.split(":");
        acc += ((+hour * 60)+ (+minutes)); 
        return acc;
     },0) 
   
}

console.log((getTotalMinutes()/60).toFixed(2));

Answer 2

请参阅 Array.reduce 实施。

const data = [
  {
    "id": 1,
    "nome": "prova2",
    "datacreazione": "2021-09-05T08:41:29.000Z",
    "costo": 23,
    "ore": "08:30",
    "IdPreventivo": 1,
    "IdUtente": 2
  },
  {
    "id": 2,
    "nome": "prova2",
    "datacreazione": "2021-09-06T08:38:26.000Z",
    "costo": 23,
    "ore": "08:30",
    "IdPreventivo": 1,
    "IdUtente": 2
  }
]
sumofhour = () => {
  const sum = data.reduce((acc, curr) => {
    let [h1, m1] = curr.ore.split(':');
    acc += (+h1 + (+m1 / 60));
    return acc;
  }, 0)
  return sum;
};
console.log(sumofhour());

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