MySQL Sequelize 一次findAll搜索两张表

Question

我创建了 3 个表

Products
|product_id | product_name| 
|-----------|-------------|
|1          | coca cola   |
|2          | pepsi       |
|3          | orange      |

Product_tags
|product_id | tag_id |
|-----------|--------|
|1          | 1      |
|2          | 1      |
|3          | 2      |

Tag_names
|tag_id     | tag_name |
|-----------|----------|
|1          | soda     |
|2          | juice    |

使用：

db.products.belongsToMany(db.tag_names, { through: 'product_tags',  as: "tags", foreignKey: 'product_id'});
db.tag_names.belongsToMany(db.products, {through: 'product_tags',  as: "products", foreignKey: 'tag_id'});

现在我想通过产品名称或标签名称搜索这些表格。例如产品名称为“coca cola”，标签为“soda”，因此搜索“coca”或搜索“sod”都会 return 它，而“sod”也会 return “pepsi”。我似乎所能做的就是让它同时要求 product_name 和 tag_name 来匹配不是我想要的查询。
谢谢，
丹尼

Answer 1

到or两个条件，你会想要使用[Op.or]运算符。然后要从顶级 where 子句访问连接子句中的 table，有一个有趣的 dollar signs 语法可以派上用场。我不确定这是否正是您想要的，但它确实 return 可口可乐和百事可乐...我在 sequelize 版本 6 中针对 postgres 数据库测试了此查询

let result = await Product.findAll({
        include: {
            model: Tag,
            as: 'tags',
            required: true
        },
        where: {
            [Op.or]: [
                { 'product_name': { [Op.like]: '%coca%' } },
                { '$tags.tag_name$': { [Op.like]: '%sod%' } }
            ]
        }
    })

并使用原始问题中的数据得出以下结果：

[
  {
    "product_id": 1,
    "product_name": "coca cola",
    "tags": [
      {
        "tag_id": 1,
        "tag_name": "soda",
        "product_tags": {
          "createdAt": "2021-09-09T18:36:24.829Z",
          "updatedAt": "2021-09-09T18:36:24.829Z",
          "product_id": 1,
          "tag_id": 1
        }
      }
    ]
  },
  {
    "product_id": 2,
    "product_name": "pepsi",
    "tags": [
      {
        "tag_id": 1,
        "tag_name": "soda",
        "product_tags": {
          "createdAt": "2021-09-09T18:36:24.861Z",
          "updatedAt": "2021-09-09T18:36:24.861Z",
          "product_id": 2,
          "tag_id": 1
        }
      }
    ]
  }
]

连同此查询：

SELECT          "product"."product_id",
                "product"."product_name",
                "tags"."tag_id" AS "tags.tag_id",
                "tags"."tag_name" AS "tags.tag_name",
                "tags->product_tags"."created_at" AS "tags.product_tags.createdAt",
                "tags->product_tags"."updated_at" AS "tags.product_tags.updatedAt",
                "tags->product_tags"."product_id" AS "tags.product_tags.product_id",
                "tags->product_tags"."tag_id" AS "tags.product_tags.tag_id"
FROM            "products" AS "product" INNER JOIN (
                        "product_tags" AS "tags->product_tags" INNER JOIN "tags" AS "tags"
                            ON "tags"."tag_id" = "tags->product_tags"."tag_id"
                    ) ON "product"."product_id" = "tags->product_tags"."product_id"
WHERE           ("product"."product_name" LIKE '%coca%' OR
                "tags"."tag_name" LIKE '%sod%');

MySQL Sequelize 一次findAll搜索两张表

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