具有完整月份和日期的年龄计算程序

Question

下午好我在bash中有一个程序可以通过输入出生年月日的数据来计算年龄。但我也想计算完成的月份和日期。我应该添加到我的代码中的条件是什么。请帮忙

echo "Enter your year of birth"
read a_nac

echo "Enter your month of birth"
read m_nac

echo "Enter your day of birth"
read d_nac

echo "-----------Birth Date---------"
echo $d_nac $m_nac $a_nac

a_act=$(date +%Y)
m_act=$(date +%m)
d_act=$(date +%d)

echo "-----------Current Date-------------"
echo $d_act $m_act $a_act

let edad=$a_act-$a_nac

if [ $m_act -lt $m_nac ]; then

    ((edad--))

    elif [ $m_nac -eq $m_act -a $d_act -lt $d_nac ]; then
       
        ((edad--))
    fi

echo "-----------Age-------------------"
echo "You have" $edad "years"

Answer 1

找到通用解决方案有点复杂。对于纪元之后的日期，我们可以将两个日期都转换为 date +%s 并进行简单的减法。

下面是一个更通用的解决方案：

echo "Enter your year of birth"
read a_nac

echo "Enter your month of birth"
read m_nac

echo "Enter your day of birth"
read d_nac

echo "-----------Birth Date---------"
echo $d_nac $m_nac $a_nac

a_act=$(date +%Y)
m_act=$(date +%-m)
d_act=$(date +%-d)

echo "-----------Current Date-------------"
echo $d_act $m_act $a_act

let years=$a_act-$a_nac

if [ $m_act -lt $m_nac ]; then
    ((years--))
    let months=$m_nac-$m_act
elif [ $m_act -ge $m_nac ]; then
    let months=$m_act-$m_nac
elif [ $m_nac -eq $m_act -a $d_act -lt $d_nac ]; then
    ((years--))
fi
if [ $d_act -lt $d_nac ]; then
    ((months--))
    let days=30-$d_nac+$d_act
else
    let days=$d_act-$d_nac
fi

echo "-----------Age-------------------"
echo "You have $years years, $months months, $days days"

行

let days=30-$d_nac+$d_act

没有考虑到不是所有的月份都是30天和闰月的情况。更正留给 reader ;)

具有完整月份和日期的年龄计算程序

Age calculation program with completed months and days

unix

bash

shell