Lodash 选择嵌套键
Lodash pick nested key
我有以下对象:
{
"coins": [],
"contract": "terra1u0t35drzyy0mujj8rkdyzhe264uls4ug3wdp3x",
"execute_msg": {
"send": {
"amount": "1000000",
"contract": "terra1ltnkx0mv7lf2rca9f8w740ashu93ujughy4s7p",
"msg": "eyJkZXBvc2l0X2NvbGxhdGVyYWwiOnt9fQ=="
}
},
"sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp"
}
{
"amount": [
{
"amount": "1000000",
"denom": "uusd"
}
],
"from_address": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp",
"to_address": "terra1ux73wdfgmu7r5us2sf0u9vdmrfxuhdk8760zzj"
}
{
"coins": [
{
"amount": "2000000",
"denom": "uusd"
}
],
"contract": "terra15dwd5mj8v59wpj0wvt233mf5efdff808c5tkal",
"execute_msg": {
"deposit_stable": {}
},
"sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp"
}
我想从每个对象中提取金额键并使用 lodash 根据该键选择数字。我已经尝试过“findKey”和“pick”运算符,但我认为没有正确使用它们,并且想知道如何获得最嵌套的数量键
您可以使用 mixin
实现的 .
获得所有对象对的扁平化版本
之后,用一个Map
来存储它们,得到amount
的值:
_.mixin({
toPairsDeep: obj => _.flatMap(
_.toPairs(obj),
([k, v]) => _.isObjectLike(v) ? _.toPairsDeep(v) : [[k, v]]
)
});
const getAmount = obj => new Map(_.toPairsDeep(obj)).get("amount");
console.log( getAmount({ "coins": [], "contract": "terra1u0t35drzyy0mujj8rkdyzhe264uls4ug3wdp3x", "execute_msg": { "send": { "amount": "1000000", "contract": "terra1ltnkx0mv7lf2rca9f8w740ashu93ujughy4s7p", "msg": "eyJkZXBvc2l0X2NvbGxhdGVyYWwiOnt9fQ==" } }, "sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp" }) );
console.log( getAmount({ "amount": [ { "amount": "1000000", "denom": "uusd" } ], "from_address": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp", "to_address": "terra1ux73wdfgmu7r5us2sf0u9vdmrfxuhdk8760zzj" }) );
console.log( getAmount({ "coins": [ { "amount": "2000000", "denom": "uusd" } ], "contract": "terra15dwd5mj8v59wpj0wvt233mf5efdff808c5tkal", "execute_msg": { "deposit_stable": {} }, "sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp" }) );
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js" integrity="sha512-WFN04846sdKMIP5LKNphMaWzU7YpMyCU245etK3g/2ARYbPK9Ub18eG+ljU96qKRCWh+quCY7yefSmlkQw1ANQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
我有以下对象:
{
"coins": [],
"contract": "terra1u0t35drzyy0mujj8rkdyzhe264uls4ug3wdp3x",
"execute_msg": {
"send": {
"amount": "1000000",
"contract": "terra1ltnkx0mv7lf2rca9f8w740ashu93ujughy4s7p",
"msg": "eyJkZXBvc2l0X2NvbGxhdGVyYWwiOnt9fQ=="
}
},
"sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp"
}
{
"amount": [
{
"amount": "1000000",
"denom": "uusd"
}
],
"from_address": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp",
"to_address": "terra1ux73wdfgmu7r5us2sf0u9vdmrfxuhdk8760zzj"
}
{
"coins": [
{
"amount": "2000000",
"denom": "uusd"
}
],
"contract": "terra15dwd5mj8v59wpj0wvt233mf5efdff808c5tkal",
"execute_msg": {
"deposit_stable": {}
},
"sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp"
}
我想从每个对象中提取金额键并使用 lodash 根据该键选择数字。我已经尝试过“findKey”和“pick”运算符,但我认为没有正确使用它们,并且想知道如何获得最嵌套的数量键
您可以使用 mixin
实现的
之后,用一个Map
来存储它们,得到amount
的值:
_.mixin({
toPairsDeep: obj => _.flatMap(
_.toPairs(obj),
([k, v]) => _.isObjectLike(v) ? _.toPairsDeep(v) : [[k, v]]
)
});
const getAmount = obj => new Map(_.toPairsDeep(obj)).get("amount");
console.log( getAmount({ "coins": [], "contract": "terra1u0t35drzyy0mujj8rkdyzhe264uls4ug3wdp3x", "execute_msg": { "send": { "amount": "1000000", "contract": "terra1ltnkx0mv7lf2rca9f8w740ashu93ujughy4s7p", "msg": "eyJkZXBvc2l0X2NvbGxhdGVyYWwiOnt9fQ==" } }, "sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp" }) );
console.log( getAmount({ "amount": [ { "amount": "1000000", "denom": "uusd" } ], "from_address": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp", "to_address": "terra1ux73wdfgmu7r5us2sf0u9vdmrfxuhdk8760zzj" }) );
console.log( getAmount({ "coins": [ { "amount": "2000000", "denom": "uusd" } ], "contract": "terra15dwd5mj8v59wpj0wvt233mf5efdff808c5tkal", "execute_msg": { "deposit_stable": {} }, "sender": "terra194rswjxvv0a2fm3f8hr4e4f3443dl3s7frsyhp" }) );
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js" integrity="sha512-WFN04846sdKMIP5LKNphMaWzU7YpMyCU245etK3g/2ARYbPK9Ub18eG+ljU96qKRCWh+quCY7yefSmlkQw1ANQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>