sequelize nested include 有一个条目为 table ，但不能从这部分查询中引用

Question

我正在使用 sequelize 和嵌套包含。我希望 table ModelC 在 id 上与 table ModelB 以及 SomeColumnId 上的 ModelA 连接。表 ModelC 和 ModelA 彼此没有关联，但它们都与 ModelB (hasMany-belongsTo) 有关联。到目前为止，这是我的代码：

const model = await ModelA.findAll({
    include: {
        model: ModelB,
        include: {
            model: ModelC,
            where: {
                [Op.and]: [
                    sequelize.literal(
                        '"ModelB->ModelC"."SomeColumnId" = "ModelA"."SomeColumnId"'
                    ),
                ],
            },
        },
    },
    subQuery: false,
    raw: true,
});

但是它给我一个错误：

Invalid reference to FROM-clause entry for table "ModelA".
There is an entry for table "ModelA", but it cannot be referenced from this part of the query.

我该如何解决这个问题？

Answer 1

我设法解决了这个问题。

const model = await ModelA.findAll({
    include: {
        model: ModelB,
        raw: true,
        include: {
            model: ModelC,
            required: false,
            where: {
                SomeColumnId: [sequelize.literal('"ModelA"."SomeColumnId"')],
            },
        },
    },
});

sequelize nested include 有一个条目为 table ，但不能从这部分查询中引用

sequelize nested include There is an entry for table , but it cannot be referenced from this part of the query

postgresql

sequelize.js