SQL Server 2008 R2：在 table 中找到第二大数字

Question

我有以下 table 一些数据，以找到第二大数字。

Table:

ColA
---------
3
23
43
673
173
373
273

Answer 1

使用这个：

select * from 
(select colA  , row_number() over(order by colA desc) as rn from Table) T
where T.rn=2

感谢 Martin/dnoeth 的评论：

最大 2 个整数可能会有问题

使用这个：

  select * from 
    (select colA  , DENSE_RANK( ) OVER (ORDER BY colA  ) as rn from Table) T
    where T.rn=2

附加信息 :(一劳永逸（学习了！，我一直在用））:

DECLARE @t TABLE(NAME NVARCHAR(MAX),val money)

insert INTO @t SELECT 'a',100
insert INTO @t SELECT 'a',100
insert INTO @t SELECT 'a',100
insert INTO @t SELECT 'a',100
insert INTO @t SELECT 'b',200
insert INTO @t SELECT 'b',200
insert INTO @t SELECT 'd',400
insert INTO @t SELECT 'e',500
insert INTO @t SELECT 'f',600
select  Name,
        val,
        ROW_NUMBER() OVER (PARTITION BY NAME  ORDER BY name),
        val/ SUM(val) OVER(PARTITION BY NAME )  AS '1AgainstTotalHimself',
        val/ SUM(val) OVER( )  AS '1AgainstOthers' , 
        NTILE(2) OVER ( PARTITION BY NAME ORDER BY name) AS 'ntile2' ,
        NTILE(2) OVER ( ORDER BY name) AS 'ntile' , -- ( 9%2=1  , so group #1 will get more number) 
        RANK( ) OVER ( ORDER BY name  ) AS  Rank,
        DENSE_RANK( ) OVER (ORDER BY name) AS DENSERANK

from @t

结果：

Answer 2

解决这个问题的一种方法是

with cte as (
    select ColA, 
           Row_number() over(order by ColA DESC) As rn
    FROM Table
)

SELECT ColA
FROM cte
WHERE rn = 2

更新 在 Martin 的正确评论之后，这里有一个更好的答案：

Select top 1 ColA
From YourTable
WHERE ColA < (
   SELECT MAX(ColA) 
   FROM YourTable
)
ORDER BY ColA DESC