与 sequelize 的一对多关系
one-to-many relationship with sequelize
我有 2 个表,用户和 users_signature 其中签名需要几个应用程序,我需要根据应用程序制作一个 select。
型号:
用户
const { INTEGER } = require('sequelize');
const Sequelize = require('sequelize');
const database = require('../../config/db');
const User_has_signature = require('./user_has_signature');
const Usuario = database.define('usuario', {
usu_id: {
type: Sequelize.INTEGER,
autoIncrement: true,
allowNull: false,
primaryKey: true
},
usu_rg: {
type: Sequelize.STRING,
},
},
{
freezeTableName: true,
createdAt: false,
updatedAt: false,
});
User.hasMany(User_has_signature, {as: 'user_has_signature'});
module.exports = User;
User_has_signature
const { INTEGER } = require('sequelize');
const Sequelize = require('sequelize');
const database = require('../../config/db');
const User_has_signature = database.define('user_has_signature', {
usu_has_signature_id: {
type: Sequelize.INTEGER,
autoIncrement: true,
allowNull: false,
primaryKey: true
},
user_usu_id: {
type: Sequelize.STRING,
},
signature_aplicativo_signature_aplicativo_id: {
type: Sequelize.STRING,
},
signature_type_signature_type_id: {
type: Sequelize.STRING,
},
},
{
freezeTableName: true,
createdAt: false,
updatedAt: false,
});
User_has_signature.associate = (models) => {
User_has_signature.belongsTo(models.User,
{ foreignKey: 'user_usu_id', as: 'users' });
};
module.exports = User_has_signature;
控制器
用户控制器
const User = require("../../model/user/user")
const User_has_signature = require("../../model/user/user_has_signature")
async index(req, res){
const user = await User.findAll({
include: [{
model: User_has_signature,
foreignKey: 'user_usu_id',
through: {
where: {signature_ttype_signature_type_id: 3}
}
}]
})
res.status(200).json(user)
return
}
The error that is returning to me in the terminal is: (node:15168)
UnhandledPromiseRejectionWarning: SequelizeEagerLoadingError:
user_has_signature is associated to usuario using an alias. You must
use the 'as' keyword to specify the alias within your include
statement
我认为您必须指定在编写查询时提供的别名:
include: [{
model: User_has_signature,
foreignKey: 'user_usu_id',
as : 'users'
through: {
where: {signature_ttype_signature_type_id: 3}
}]
无论哪种方式,我在 Typescript 中更多地使用 Sequelize,所以我不确定语法。
它处理一对多关系的方式不是我见过的最清楚的(像 Symfony 或 Spring)
我有 2 个表,用户和 users_signature 其中签名需要几个应用程序,我需要根据应用程序制作一个 select。
型号:
用户
const { INTEGER } = require('sequelize');
const Sequelize = require('sequelize');
const database = require('../../config/db');
const User_has_signature = require('./user_has_signature');
const Usuario = database.define('usuario', {
usu_id: {
type: Sequelize.INTEGER,
autoIncrement: true,
allowNull: false,
primaryKey: true
},
usu_rg: {
type: Sequelize.STRING,
},
},
{
freezeTableName: true,
createdAt: false,
updatedAt: false,
});
User.hasMany(User_has_signature, {as: 'user_has_signature'});
module.exports = User;
User_has_signature
const { INTEGER } = require('sequelize');
const Sequelize = require('sequelize');
const database = require('../../config/db');
const User_has_signature = database.define('user_has_signature', {
usu_has_signature_id: {
type: Sequelize.INTEGER,
autoIncrement: true,
allowNull: false,
primaryKey: true
},
user_usu_id: {
type: Sequelize.STRING,
},
signature_aplicativo_signature_aplicativo_id: {
type: Sequelize.STRING,
},
signature_type_signature_type_id: {
type: Sequelize.STRING,
},
},
{
freezeTableName: true,
createdAt: false,
updatedAt: false,
});
User_has_signature.associate = (models) => {
User_has_signature.belongsTo(models.User,
{ foreignKey: 'user_usu_id', as: 'users' });
};
module.exports = User_has_signature;
控制器
用户控制器
const User = require("../../model/user/user")
const User_has_signature = require("../../model/user/user_has_signature")
async index(req, res){
const user = await User.findAll({
include: [{
model: User_has_signature,
foreignKey: 'user_usu_id',
through: {
where: {signature_ttype_signature_type_id: 3}
}
}]
})
res.status(200).json(user)
return
}
The error that is returning to me in the terminal is: (node:15168) UnhandledPromiseRejectionWarning: SequelizeEagerLoadingError: user_has_signature is associated to usuario using an alias. You must use the 'as' keyword to specify the alias within your include statement
我认为您必须指定在编写查询时提供的别名:
include: [{
model: User_has_signature,
foreignKey: 'user_usu_id',
as : 'users'
through: {
where: {signature_ttype_signature_type_id: 3}
}]
无论哪种方式,我在 Typescript 中更多地使用 Sequelize,所以我不确定语法。
它处理一对多关系的方式不是我见过的最清楚的(像 Symfony 或 Spring)