如何在 python 的 super( ) 函数中指定使用哪个父 class？

Question

My Objective：在子 class 中创建名为 [identify2] 的方法，该方法从 Parent2 class 调用 [identify] 方法。这必须使用 super() 关键字来完成。

我的问题：两个父 class 中的方法名称相同。但我只想使用 super() 关键字与 parent2 class 的方法有关。我该怎么办？

class Parent1:
  def identify(self):
    return "This method is called from Parent1"
    
class Parent2:
  def identify(self):
    return "This method is called from Parent2"
    
# declare child class here
class child(Parent1, Parent2):
  def identify(self):
    return "This method is called from Child"
  def identify2(self):
    super().identify()  # I want to call the method of Parent2 class, how?     
  
  
child_object = child()
#                                           Expected output:
print( child_object.identify() )        # This method is called from Child
print( child_object.identify2() )       # This method is called from Parent2

Answer 1

super可以用类型和对象参数调用，见documentation。类型参数确定在 mro 顺序中的 class 之后将开始搜索方法。在这种情况下，要获得 Parent2 的方法，搜索应该在 Parent1:

之后开始

class Parent1:
    def identify(self):
        return "This method is called from Parent1"
    
class Parent2:
    def identify(self):
        return "This method is called from Parent2"
    
# declare child class here
class Child(Parent1, Parent2):
    def identify(self):
        return "This method is called from Child"
    
    def identify2(self):
        return super(Parent1, self).identify()
  
  
child_object = Child()
#                                           Expected output:
print( child_object.identify() )        # This method is called from Child
print( child_object.identify2() )       # This method is called from Parent2

这给出：

This method is called from Child
This method is called from Parent2

如何在 python 的 super( ) 函数中指定使用哪个父 class？

How to specify which parent class to use in super( ) function in python?

python

oop

inheritance

overriding