Return 输入有效会员编号时未执行语句
Return statement not executed when valid member number is entered
大家早上好,
因此,我尝试创建一个帐户 class,其扫描方法采用“虚拟”会员卡扫描,但是,当我在输入中输入有效 card_number字段 returns 另一个输入字段,但是如果我输入无效 card_number 它 returns 无效 ID
这是我的代码,请问我哪里出错了?
from enum import Enum
from abc import ABC, abstractmethod
import csv
import json
from datetime import datetime, timedelta, date
membersJsonPath = 'members.json'
class BookStatus(Enum):
AVAILABLE, RESERVED, LOANED, LOST = 1, 2, 3, 4
class ReservationStatus(Enum):
WAITING, PENDING, CANCELED, NONE = 1, 2, 3, 4
class AccountStatus(Enum):
ACTIVE, CLOSED, CANCELED, NONE = 1, 2, 3, 4
class Account(ABC):
def __init__(self, status=AccountStatus.ACTIVE):
self.__id = self.scan_id()
self.__status = status
def scan_id(self):
with open(membersJsonPath, 'r') as membersJson:
data = json.load(membersJson)
input_id = input("Please enter your member ID: ")
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
else:
return "Invalid ID"
a = Account()
a.scan_id()
这是我从 CSV 文件创建的 json 文件的一部分
{
"members": [
{
"\u00ef\u00bb\u00bfid": "1",
"first_name": "Adelaide",
"last_name": "Cunningham",
"gender": "Female",
"email": "a.cunningham@randatmail.com",
"card_number": "13"
},
{
"\u00ef\u00bb\u00bfid": "2",
"first_name": "Charlie",
"last_name": "Roberts",
"gender": "Male",
"email": "c.roberts@randatmail.com",
"card_number": "22"
},
{
"\u00ef\u00bb\u00bfid": "3",
"first_name": "Eric",
"last_name": "Cooper",
"gender": "Male",
"email": "e.cooper@randatmail.com",
"card_number": "33"
},
{
"\u00ef\u00bb\u00bfid": "4",
"first_name": "Cadie",
"last_name": "Hall",
"gender": "Female",
"email": "c.hall@randatmail.com",
"card_number": "43"
}
]
}
问题出在这个for循环中:
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
else:
return "Invalid ID"
这里,如果input_id
等于第一个会员的卡号,则return是欢迎信息,否则"Invalid ID"
。你想扫描所有的卡号,只有 return "Invalid ID"
如果 none 匹配,所以第二个 return 语句应该在 for 循环结束之后:
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
return "Invalid ID"
大家早上好,
因此,我尝试创建一个帐户 class,其扫描方法采用“虚拟”会员卡扫描,但是,当我在输入中输入有效 card_number字段 returns 另一个输入字段,但是如果我输入无效 card_number 它 returns 无效 ID
这是我的代码,请问我哪里出错了?
from enum import Enum
from abc import ABC, abstractmethod
import csv
import json
from datetime import datetime, timedelta, date
membersJsonPath = 'members.json'
class BookStatus(Enum):
AVAILABLE, RESERVED, LOANED, LOST = 1, 2, 3, 4
class ReservationStatus(Enum):
WAITING, PENDING, CANCELED, NONE = 1, 2, 3, 4
class AccountStatus(Enum):
ACTIVE, CLOSED, CANCELED, NONE = 1, 2, 3, 4
class Account(ABC):
def __init__(self, status=AccountStatus.ACTIVE):
self.__id = self.scan_id()
self.__status = status
def scan_id(self):
with open(membersJsonPath, 'r') as membersJson:
data = json.load(membersJson)
input_id = input("Please enter your member ID: ")
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
else:
return "Invalid ID"
a = Account()
a.scan_id()
这是我从 CSV 文件创建的 json 文件的一部分
{
"members": [
{
"\u00ef\u00bb\u00bfid": "1",
"first_name": "Adelaide",
"last_name": "Cunningham",
"gender": "Female",
"email": "a.cunningham@randatmail.com",
"card_number": "13"
},
{
"\u00ef\u00bb\u00bfid": "2",
"first_name": "Charlie",
"last_name": "Roberts",
"gender": "Male",
"email": "c.roberts@randatmail.com",
"card_number": "22"
},
{
"\u00ef\u00bb\u00bfid": "3",
"first_name": "Eric",
"last_name": "Cooper",
"gender": "Male",
"email": "e.cooper@randatmail.com",
"card_number": "33"
},
{
"\u00ef\u00bb\u00bfid": "4",
"first_name": "Cadie",
"last_name": "Hall",
"gender": "Female",
"email": "c.hall@randatmail.com",
"card_number": "43"
}
]
}
问题出在这个for循环中:
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
else:
return "Invalid ID"
这里,如果input_id
等于第一个会员的卡号,则return是欢迎信息,否则"Invalid ID"
。你想扫描所有的卡号,只有 return "Invalid ID"
如果 none 匹配,所以第二个 return 语句应该在 for 循环结束之后:
for member in data['members']:
if member['card_number'] == input_id:
return ("Welcome, " + member['first_name'] + "!")
return "Invalid ID"