每个框包含多个信息的数组

Question

所以我有这个练习题，我应该在其中创建一个包含员工信息的数组并将其传递给 class；我的代码有问题，我似乎无法弄清楚。

代码的目的是：将代码中看到的信息放入数组中，然后传递给 class 中的方法，然后打印出来给用户。（class 中的代码非常好，因此这里没有包含它）。

如果有人能提供帮助，那就太好了。

谢谢。

//代码。

    // The Scanners.
    Scanner input = new Scanner(System.in);
    Scanner scan = new Scanner(System.in);
    
    // Taking Number Of Employees From The User.
    System.out.println("How many employees are there: ");
    int numberOfEmployees = input.nextInt();
    
    //Creating An Array With The Size Of Employees Entered By The User.
    Employee[] E = new Employee[numberOfEmployees];
    
    // Filling Out Information About Employees In Array.
    for(int i = 0; i <= E.length-1; i++){
        System.out.println("Enter employee " + i + "'s name: ");
        String name = scan.nextLine();
        
        System.out.println("Enter employee " + i + "'s birth date: ");
        String bday = scan.nextLine();
        
        System.out.println("Enter employee " + i + "'s salary: ");
        double salary = input.nextDouble();
        
        System.out.println("Enter employee " + i + "'s overtime: ");
        int overtime = input.nextInt();
        
        E[i] = (name, bday, salary, overtime);
    }
    
    System.out.println("Employee's Information"
            + "\n----------------------"
            + "\n----------------------");
    
    for(int i = 0; i <= E.length-1; i++){
        E[i].print();
    }
}

Answer 1

这里有两个问题需要解决。

首先，不要创建多个 Scanner 对象，从 System.in 读取。我知道你这样做是因为这个问题（检查出来）：Scanner is skipping nextLine() after using next() or nextFoo()? - 但是除了创建另一个 Scanner.

之外还有另一种解决方案

第二期在这里：

E[i] = (name, bday, salary, overtime);

您有一个 Employee[] 正在尝试填写。但是你的语法错误。你实际上想创建一个 new Employee(...) 来填充你的数组。

所以这一行应该是正确的（前提是 Employee 有一个给定类型的构造函数）：

E[i] = new Employee(name, bday, salary, overtime);

在您的代码片段中考虑这一点时：

Scanner scan = new Scanner(System.in);
// Taking Number Of Employees From The User.
System.out.println("How many employees are there: ");
int numberOfEmployees = scan.nextInt();
scan.nextLine(); // <- reads the newline from the console

//Creating An Array With The Size Of Employees Entered By The User.
Employee[] E = new Employee[numberOfEmployees];

// Filling Out Information About Employees In Array.
for(int i = 0; i <= E.length-1; i++){
    System.out.println("Enter employee " + i + "'s name: ");
    String name = scan.nextLine();
    
    System.out.println("Enter employee " + i + "'s birth date: ");
    String bday = scan.nextLine();
    
    System.out.println("Enter employee " + i + "'s salary: ");
    double salary = scan.nextDouble();
    
    System.out.println("Enter employee " + i + "'s overtime: ");
    int overtime = scan.nextInt();
    
    // create a new employee with the entered information and save in the array
    E[i] = new Employee(name, bday, salary, overtime);
}

Answer 2

我不确定双扫描仪。

显而易见的是，由于您定义了一个 Employee 对象类型的空数组，该数组只能容纳 Employee 对象。

Employee[] E = new Employee[numberOfEmployees]

要定义一个对象，需要为其分配一块内存，如：

new Employee(name, bday, salary, overtime);

然后赋值到数组E

E[i] = new Employee(name, bday, salary, overtime);

我希望把事情搞清楚。

每个框包含多个信息的数组

Arrays With Multiple Information Per Box

java

arrays

methods

class