php 链接刷新错误

Question

你好，我在登录后遇到这个登录脚本的问题，当它必须转到链接时，它只是让我重新登录，我不明白为什么我有一个搜索脚本而不是链接它现在可以工作，但不是很多。

<html>
<head>
 <title>User Login Form - PHP MySQL Ligin System | W3Epic.com</title>
</head>
<body>
<h1>User Login Form - PHP MySQL Ligin System | W3Epic.com</h1>
<?php
if (!isset($_POST['submit']) || !isset($_SESSION['username'])){
?>

<!-- The HTML login form -->
 <form action="<?=$_SERVER['PHP_SELF']?>" method="post">
  Username: <input type="text" name="username" /><br />
  Password: <input type="password" name="password" /><br />
 
  <input type="submit" name="submit" value="Login" />
 </form>
<?php
} else {
 require_once("db_const.php");
 $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
 # check connection
 if ($mysqli->connect_errno) {
  echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
  exit();
 }
 
 $username = $_POST['username'];
 $password = $_POST['password'];
  $_SESSION['username'] = $_POST['username'];
 $sql = "SELECT * from members WHERE username LIKE '{$username}' AND password LIKE '{$password}' LIMIT 1";
 $result = $mysqli->query($sql);
 if (!$result->num_rows == 1) {
  echo "<p>Invalid username/password combination</p>";
 } else {
  echo "<table align=center><tr>
  <font color=#000000  face=Arial, Helvetica, sans-serif size=+2>
  <td align=center><p>Logged in successfully</p></td></tr>";
  echo "<tr><td align=center><p>welcome!</p></td></tr>";
  echo "<tr><td align=center><p>what wood you like to work whit today ". $username . "!</p></td></tr></table>";
  
  echo "<table align=center><tr><td align=center><a href=adminsearch.php>
  <class\= color=#000000; face=Arial Black, Gadget, sans-seri;style=”text-decoration:none; size=+2>Admin</a></td>";
  
  echo "<td align=center>&hArr;</td>";
  
  echo "<td align=center><a href=constructionsearch.php>
  <class\= color=#000000; face=Arial Black, Gadget, sans-seri;style=”text-decoration:none; size=+2>Construction</a></td>";
  
  echo "<td align=center>&hArr;</td>";
  
  echo "<td align=center><a href=drivingsearch.php>
  <class\= color=#000000; face=Arial Black, Gadget, sans-seri;style=”text-decoration:none; size=+2>Driving</a></td>";
  
  echo "<td align=center>&hArr;</td>";
  
  echo "<td align=center><a href=industrialsearch.php>
  <class\= color=#000000; face=Arial Black, Gadget, sans-seri;style=”text-decoration:none; size=+2>Industrial</a></td></font></table>";
  
  
}
}
?>

Answer 1

您的脚本现在的方式是，如果未提交表单，它只会显示登录表单。所以当你导航到其他链接时，表单没有提交，所以它会显示表单。您需要使用 cookie 或会话跟踪已登录的用户。在确认 username/password 后将其添加到您的代码中：

$_SESSION['username'] = $_POST['username'];

然后代替这个：

if (!isset($_POST['submit'])){

使用这个：

if (!isset($_POST['submit']) || !isset($_SESSION['username']){

php 链接刷新错误

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