使用 oracle sql 查找最后完成的任务
Find last finish task using oracle sql
我需要在每个组中找到使用 sql 的最后一个完成任务。我有两个条件。 construction_type = 0 和 construction_type in (1, 2)。对于 construction_type = 0。只有完成的任务才会被获取。但是 construction_type in (1, 2)。可以获取已完成和未完成的任务。我进行了查询，但问题是如果任务已完成并且输入了一些未完成的新任务，那么这个未完成的任务就会排在最前面。我尝试了不同的顺序但不知何故无法在顶部获得最后完成的任务
construction_type in (1, 2)。对于 construction_type = 0 没有问题，因为只有完成的任务才会被提取。
我在 task_last_modified_date 前订购。如果某个新任务将进入，那么它具有最高 task_last_modified_date。这就是为什么我未完成的任务排在首位。它应该类似于 latest task_last_modified_date with completed task。但是我不知道该怎么做。
这是示例数据
CREATE TABLE project_complete_data (CONSTRUCTION_TYPE, PROJECT_ID, PROJ_COMPANY_NAME, CUSTOM_LOT_NO, LOT_STATUS, SCHEDULE_TASK_ID, TASK_NAME, TASK_STATUS, TASK_ACTUAL_END_DATE, TASK_FINISH_DATE, TASK_FINISHED, TASK_LAST_MODIFIED_DATE, PO_TOTAL_AMOUNT, PO_STATUS, PO_TYPE) AS
SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961162, 'electrical rough', 101, DATE '2021-12-13', DATE '2021-11-19', 0, TO_DATE('2021-11-16 14:44:04', 'YYYY-MM-DD hh24:mi:ss'), 49.7, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961161, 'plumbing rough', 101, DATE '2021-12-06', DATE '2021-11-12', 1, TO_DATE('2021-11-15 15:22:13', 'YYYY-MM-DD hh24:mi:ss'), 0.3, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961159, 'roof framing', 101, DATE '2021-11-29', DATE '2021-11-15', 1, TO_DATE('2021-11-15 13:04:37', 'YYYY-MM-DD hh24:mi:ss'), 10, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961158, 'second floor framing', 101, DATE '2021-11-15', DATE '2021-11-09', 1, TO_DATE('2021-11-09 15:22:42', 'YYYY-MM-DD hh24:mi:ss'), 50, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '01a', 103, 10134563, 'Rough-In Plumbing', 101, DATE '2009-12-17', DATE '2014-09-01', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '02', 103, 2213016, 'Update Lender Info in BT - Sales Rep', 101, DATE '2005-06-28', DATE '2005-10-11', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 0, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 33, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', 'testpa01', 102, 10959716, 'HVAC rough', 101, DATE '2021-09-17', DATE '2021-09-15', 0, TO_DATE('2021-11-02 12:28:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 100 FROM DUAL;
这里是查询
select
proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (PARTITION BY custom_lot_no ORDER BY to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101 THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100 THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in ('100', '101')
AND lot_status in ('102', '103')
And task_status = 101
AND (
(construction_type = 0 AND task_finished = 1 and (schedule_task_id is not null or schedule_task_id > 0))
OR (construction_type in ('1', '2') AND task_finished in ('1', '0'))
)
order by custom_lot_no, to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc;
此查询给出以下结果
如您所见，最高记录有最高 last_modified_date_time，并且在 last_task_finish_seq 处达到 1。但是此任务未完成，因为它 task_finished is 0。所以第一个记录应该是第二个，因为last_modified_date_time虽然少了但是已经完成了。它最后完成，因为它比其他已完成的任务更高 last_modified_date_time。
我该怎么做？实际上，在将每个组记录放在首位之后，我会使用类似
的东西
`select * from (above query) where LAST_TASK_FINISH_SEQ = 1;`
因为那时我知道我最后完成的任务在每个组的顶部。
谢谢
要获取最近完成的行（或最新的行，如果没有行完成且construction_type IN (1,2)），您可以使用：
SELECT *
FROM (
SELECT *
FROM project_complete_data
WHERE project_id = 511
AND po_status IN (100, 101)
AND lot_status IN (102, 103)
AND task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id IS NOT NULL)
OR construction_type IN (1, 2)
)
)
MATCH_RECOGNIZE (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date DESC
ALL ROWS PER MATCH
PATTERN ( ^ latest_finished_row )
DEFINE
latest_finished_row AS 1 = 1
)
如果您想在不过滤的情况下对行进行排序：
select proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss')
AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date desc
) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101
THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100
THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in (100, 101)
AND lot_status in (102, 103)
And task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id is not null
)
OR ( construction_type in (1, 2)
AND task_finished in (1, 0)
)
)
order by custom_lot_no, task_last_modified_date desc;
db<>fiddle here
我需要在每个组中找到使用 sql 的最后一个完成任务。我有两个条件。 construction_type = 0 和 construction_type in (1, 2)。对于 construction_type = 0。只有完成的任务才会被获取。但是 construction_type in (1, 2)。可以获取已完成和未完成的任务。我进行了查询，但问题是如果任务已完成并且输入了一些未完成的新任务，那么这个未完成的任务就会排在最前面。我尝试了不同的顺序但不知何故无法在顶部获得最后完成的任务
construction_type in (1, 2)。对于 construction_type = 0 没有问题，因为只有完成的任务才会被提取。
我在 task_last_modified_date 前订购。如果某个新任务将进入，那么它具有最高 task_last_modified_date。这就是为什么我未完成的任务排在首位。它应该类似于 latest task_last_modified_date with completed task。但是我不知道该怎么做。
这是示例数据
CREATE TABLE project_complete_data (CONSTRUCTION_TYPE, PROJECT_ID, PROJ_COMPANY_NAME, CUSTOM_LOT_NO, LOT_STATUS, SCHEDULE_TASK_ID, TASK_NAME, TASK_STATUS, TASK_ACTUAL_END_DATE, TASK_FINISH_DATE, TASK_FINISHED, TASK_LAST_MODIFIED_DATE, PO_TOTAL_AMOUNT, PO_STATUS, PO_TYPE) AS
SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961162, 'electrical rough', 101, DATE '2021-12-13', DATE '2021-11-19', 0, TO_DATE('2021-11-16 14:44:04', 'YYYY-MM-DD hh24:mi:ss'), 49.7, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961161, 'plumbing rough', 101, DATE '2021-12-06', DATE '2021-11-12', 1, TO_DATE('2021-11-15 15:22:13', 'YYYY-MM-DD hh24:mi:ss'), 0.3, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961159, 'roof framing', 101, DATE '2021-11-29', DATE '2021-11-15', 1, TO_DATE('2021-11-15 13:04:37', 'YYYY-MM-DD hh24:mi:ss'), 10, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961158, 'second floor framing', 101, DATE '2021-11-15', DATE '2021-11-09', 1, TO_DATE('2021-11-09 15:22:42', 'YYYY-MM-DD hh24:mi:ss'), 50, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '01a', 103, 10134563, 'Rough-In Plumbing', 101, DATE '2009-12-17', DATE '2014-09-01', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '02', 103, 2213016, 'Update Lender Info in BT - Sales Rep', 101, DATE '2005-06-28', DATE '2005-10-11', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 0, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 33, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', 'testpa01', 102, 10959716, 'HVAC rough', 101, DATE '2021-09-17', DATE '2021-09-15', 0, TO_DATE('2021-11-02 12:28:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 100 FROM DUAL;
这里是查询
select
proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (PARTITION BY custom_lot_no ORDER BY to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101 THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100 THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in ('100', '101')
AND lot_status in ('102', '103')
And task_status = 101
AND (
(construction_type = 0 AND task_finished = 1 and (schedule_task_id is not null or schedule_task_id > 0))
OR (construction_type in ('1', '2') AND task_finished in ('1', '0'))
)
order by custom_lot_no, to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc;
此查询给出以下结果
如您所见，最高记录有最高 last_modified_date_time，并且在 last_task_finish_seq 处达到 1。但是此任务未完成，因为它 task_finished is 0。所以第一个记录应该是第二个，因为last_modified_date_time虽然少了但是已经完成了。它最后完成，因为它比其他已完成的任务更高 last_modified_date_time。
我该怎么做？实际上，在将每个组记录放在首位之后，我会使用类似
的东西`select * from (above query) where LAST_TASK_FINISH_SEQ = 1;`
因为那时我知道我最后完成的任务在每个组的顶部。
谢谢
要获取最近完成的行（或最新的行，如果没有行完成且construction_type IN (1,2)），您可以使用：
SELECT *
FROM (
SELECT *
FROM project_complete_data
WHERE project_id = 511
AND po_status IN (100, 101)
AND lot_status IN (102, 103)
AND task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id IS NOT NULL)
OR construction_type IN (1, 2)
)
)
MATCH_RECOGNIZE (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date DESC
ALL ROWS PER MATCH
PATTERN ( ^ latest_finished_row )
DEFINE
latest_finished_row AS 1 = 1
)
如果您想在不过滤的情况下对行进行排序：
select proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss')
AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date desc
) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101
THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100
THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in (100, 101)
AND lot_status in (102, 103)
And task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id is not null
)
OR ( construction_type in (1, 2)
AND task_finished in (1, 0)
)
)
order by custom_lot_no, task_last_modified_date desc;
db<>fiddle here