我怎样才能改变矩形的大小

Question

我用的是Rabbid76的一个功能。有了这个功能，我可以旋转一个矩形。矩形得到 image.I 的大小想要更改矩形的大小，使其小于图像。我尝试改变左上角和右上角。它没有用。

import pygame

pygame.init()
screen = pygame.display.set_mode((400, 400))
font = pygame.font.SysFont(None, 50)
clock = pygame.time.Clock()

#orig_image = font.render("rotated rectangle", True, (255, 0, 0))
angle =0
orig_image = pygame.image.load("Bilder/baum2.png")
rotated_image = pygame.transform.rotate(orig_image, angle)

def draw_rect_angle(surf, rect, pivot, angle):   
    rect.topleft = (rect.topleft[0] +25 , rect.topleft[1])
    rect.topright = (rect.topright[0] -25, rect.topright[1])    
    pts = [rect.topleft, rect.topright, rect.bottomright, rect.bottomleft]
    pts = [(pygame.math.Vector2(p) - pivot).rotate(-angle) + pivot for p in pts]
    pygame.draw.lines(surf, (255, 255, 0), True, pts, 3)

run = True
while run:
    clock.tick(60)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False    

    screen.fill(0)
    screen_center = screen.get_rect().center
    screen.blit(rotated_image, rotated_image.get_rect(center = screen_center))
    rect = orig_image.get_rect(center = screen_center)
    draw_rect_angle(screen, rect, screen_center, angle)
    pygame.display.flip()

pygame.quit()
exit()

Answer 1

在下面的代码中：

    rect.topleft = (rect.topleft[0] +25 , rect.topleft[1])
    rect.topright = (rect.topright[0] -25, rect.topright[1])

topleft[0]就是top； topright[0] 和 top.

一样

然后 top + 25、top - 25 等于 top + 0 所以什么都没有改变。

也许你想修改 bottomright.

小提示：逐行调试，注意变量的变化，更容易发现程序执行与预期效果不一致的地方

Answer 2

您所要做的就是缩小输入矩形的大小。使用 pygame.Rect.inflate with with 负值来减小矩形的大小：

def draw_rect_angle(surf, orig_rect, pivot, angle):

    rect = orig_rect.inflate(-25, -25)

    pts = [rect.topleft, rect.topright, rect.bottomright, rect.bottomleft]
    pts = [(pygame.math.Vector2(p) - pivot).rotate(-angle) + pivot for p in pts]
    pygame.draw.lines(surf, (255, 255, 0), True, pts, 3)

我怎样才能改变矩形的大小

how can i change the size of a rectangle

python

pygame