查询一个 JSONB 对象数组
Query a JSONB object array
我做了一个数据库 Fiddle table 有点像 https://www.db-fiddle.com/f/4jyoMCicNSZpjMt4jFYoz5/3382
table 中的数据如下所示
[
{
"id": 1,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "No",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": [
"Red",
"Blue"
],
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
},
{
"id": 2,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": "Black",
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
},
{
"id": 3,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "No",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": [
"Black",
"Red"
],
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
}
]
我有一个问题select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%');
但是不能做一个以上的对象,比如select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%') AND (items.id = '2' AND items.value like '%Yes%');
对象中的值字段也可以是数组或单个值..unpredictable..我觉得我很接近但也不确定我是否在第一个中使用了正确的查询地点。
如有任何帮助,我们将不胜感激!
编辑
select * from form_responses where(
questionnaire_response @> '[{"id": "2", "value":"No"},{"id": "3", "value":["Red"]}]')
似乎可行,但不确定这是否是最好的方法
您当前的查询 returns 每项一个结果行。 None 这些行同时具有 id = 3
和 id = 2
。如果您的目标是 select 整个表单响应,则需要使用子查询(或者更确切地说,其中两个):
SELECT *
FROM form_responses
WHERE EXISTS(
SELECT *
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '3'
AND items.value like '%Black%'
)
AND EXISTS(
SELECT *
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '2'
AND items.value like '%Yes%'
);
或者
SELECT *
FROM form_responses
WHERE (
SELECT value
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '3'
) like '%Black%'
AND (
SELECT value
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '2'
) like '%Yes%';
更好的替代方法是使用 json path 查询:
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes"'
AND questionnaire_response @@ '$[*]?(@.id == "3").value[*] == "Black"'
-- in one:
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes" && $[*]?(@.id == "3").value[*] == "Black"'
[*]
甚至对 sometimes-string-sometimes-array 值具有正确的语义。如果您知道具有这些 ID 的项目的索引,您甚至可以简化为
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[0].value == "Yes" && $[2].value[*] == "Black"'
我做了一个数据库 Fiddle table 有点像 https://www.db-fiddle.com/f/4jyoMCicNSZpjMt4jFYoz5/3382
table 中的数据如下所示
[
{
"id": 1,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "No",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": [
"Red",
"Blue"
],
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
},
{
"id": 2,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": "Black",
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
},
{
"id": 3,
"form_id": 1,
"questionnaire_response": [
{
"id": "1",
"title": "Are you alive?",
"value": "Yes",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "2",
"title": "Did you sleep good?",
"value": "No",
"form_id": 0,
"shortTitle": "",
"description": ""
},
{
"id": "3",
"title": "Whats favorite color(s)?",
"value": [
"Black",
"Red"
],
"form_id": 0,
"shortTitle": "",
"description": ""
}
]
}
]
我有一个问题select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%');
但是不能做一个以上的对象,比如select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%') AND (items.id = '2' AND items.value like '%Yes%');
对象中的值字段也可以是数组或单个值..unpredictable..我觉得我很接近但也不确定我是否在第一个中使用了正确的查询地点。
如有任何帮助,我们将不胜感激!
编辑
select * from form_responses where(
questionnaire_response @> '[{"id": "2", "value":"No"},{"id": "3", "value":["Red"]}]')
似乎可行,但不确定这是否是最好的方法
您当前的查询 returns 每项一个结果行。 None 这些行同时具有 id = 3
和 id = 2
。如果您的目标是 select 整个表单响应,则需要使用子查询(或者更确切地说,其中两个):
SELECT *
FROM form_responses
WHERE EXISTS(
SELECT *
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '3'
AND items.value like '%Black%'
)
AND EXISTS(
SELECT *
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '2'
AND items.value like '%Yes%'
);
或者
SELECT *
FROM form_responses
WHERE (
SELECT value
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '3'
) like '%Black%'
AND (
SELECT value
FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
WHERE items.id = '2'
) like '%Yes%';
更好的替代方法是使用 json path 查询:
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes"'
AND questionnaire_response @@ '$[*]?(@.id == "3").value[*] == "Black"'
-- in one:
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes" && $[*]?(@.id == "3").value[*] == "Black"'
[*]
甚至对 sometimes-string-sometimes-array 值具有正确的语义。如果您知道具有这些 ID 的项目的索引,您甚至可以简化为
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[0].value == "Yes" && $[2].value[*] == "Black"'