如何将 ULID 类型转换为 UUID 类型？

Question

我正在查看这个 ULID 生成器 https://wvlet.org/airframe/docs/airframe-ulid 但不太确定如何将 ULID 转换为 UUID。我尝试了下面的代码，期望前 48 位看起来相似，但这些位随机出现

scala> import java.util.UUID
scala> import wvlet.airframe.ulid.ULID
scala> (0 to 100).map(_ => UUID.nameUUIDFromBytes(ULID.newULID.toBytes))

val res36: IndexedSeq[java.util.UUID] = Vector(3d938b6f-167d-3915-9491-ca20400efc24, 72b562fa-7866-3401-ae8d-10fabf43864d, b60d0802-bf77-3cc3-a3de-fc1943fcdd8c, 4189103e-f284-3da3-a4ac-f43381197e64, c58829d6-31dc-33ed-accb-c76022b85f05, 765ed5fb-9542-332b-8ae7-eb00a4a4e313, a2fcbfd9-28be-374d-b7bc-97ade744e0f5, 50056d54-2eb7-3a50-bc91-ccbf279ef989, b49b8a86-ab8c-3e82-b06e-00460a5b600b, bb965b65-03bb-3785-a77b-4a858f190de1, 47e980bc-48b0-37ed-8d39-af3769f7758a, 57cf5eae-996b-3f1a-a24f-2594287f9c83, be38a6f3-df4d-31e5-9521-0078526fb6a5, fb1fa782-311d-322f-b902-ddf318f971c6, b64c5980-624e-3ea6-8813-94f8329fec32, 4c368e3d-3448-3d56-b8bd-abd84bc62d8a, aad5500b-720a-3445-8b06-e0e5b721ee5f, fb774e2c-9966-33be-bc59-6e88cd095178, 8265102b-e8fe-381f-bd51-49660dd63c13, 6b...

Answer 1

未经测试且不是很干净：

import java.util.UUID
import wvlet.airframe.ulid.{ULID, CrockfordBase32}

val ulid = ULID.newULID
val (hi, lo) = CrockfordBase32.decode128bits(ulid.toString)
val uuid = new UUID(hi, lo)

UUID 没有将 16 字节数组转换为 UUID 的构造函数。您需要将数组转换为 2 个 long（2x 8 字节）。

如何将 ULID 类型转换为 UUID 类型？

How would one convert a ULID type to UUID type?

scala