使用 Filtered String 和 Remove from Original Array 过滤字符串数组

Question

我想从包含单词 Evil (filterString) 的数组中删除一些元素。

let guests = ["Partner", "Evil Nice Relative 1", "Nice Relative 2", "Evil One", "another evil", "another one", "another evil is here", "strange Evil is here", "someone Nicer", "Ugly Evil Bad"];

const filteredArray = [];
const filterString = "Evil";

function checkEvil() {
    guests.filter((element, index) => {
        if (element.toLowerCase().indexOf(filterString.toLowerCase()) !== -1) {
            console.log(index);
            guests.splice(index,1);
        } else {
            filteredArray.push(element);
        }
    });
    console.log(guests);
}

这是我得到的原始数组 (guests):


    ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer']

只希望在所需字符串 (Evil) 被过滤后更新 guests 数组。

Answer 1

既然你想改变原始数组，那么你可以这样做：

let guests = [
  "Partner",
  "Evil Nice Relative 1",
  "Nice Relative 2",
  "Evil One",
  "another evil",
  "another one",
  "another evil is here",
  "strange Evil is here",
  "someone Nicer",
  "Ugly Evil Bad",
];

const filterString = "Evil";

function checkEvil() {
  for (let i = guests.length - 1; i >= 0; i--) {
    const element = guests[i];
    if (element.toLowerCase().indexOf(filterString.toLowerCase()) !== -1) {
      guests.splice(i, 1);
    }
  }
  console.log(guests);
}

checkEvil();

1) 您可以使用 filter and match 轻松获得结果：

const arr = [
  "Partner",
  "Nice Relative 2",
  "another evil",
  "another one",
  "strange Evil is here",
  "someone Nicer",
];
const result = arr.filter((s) => !s.match(/evil/i));
console.log(result);

2) 您也可以使用 forEach 并匹配为：

let guests = [
  "Partner",
  "Evil Nice Relative 1",
  "Nice Relative 2",
  "Evil One",
  "another evil",
  "another one",
  "another evil is here",
  "strange Evil is here",
  "someone Nicer",
  "Ugly Evil Bad",
];

const filteredArray = [];
const filterString = "Evil";

function checkEvil() {
  guests.forEach(element => {
    if (!element.match(/evil/i)) filteredArray.push(element);
  });
}
checkEvil();
console.log(filteredArray);

Answer 2

<script>
    var list = ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer'];
    var new_list = [];

    for(var i=0; i<list.length; i++) {
        if(!list[i].toLowerCase().includes('evil')) {
            new_list.push(list[i]);
        }
    }

    console.log(new_list);
</script>

Answer 3

定义一个模式然后按它过滤

var arr = ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer'];
const PATTERN = 'EVIL';
arr = arr.filter(str => str.toUpperCase().indexOf(PATTERN) === -1);

Answer 4

您可以过滤每个值不包含 'evil' 单词的数组：

const arr = ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer'];
const filteredArr = arr.filter(val=>!val.toLowerCase().includes('evil'))
console.log(filteredArr)

使用 Filtered String 和 Remove from Original Array 过滤字符串数组

Filter an Array of strings using Filtered String and Remove from Original Array

javascript

arrays

filtering

array-splice