提取可选数量的单词

Question

我有这样的字符串-

string="John has got 6 cats but I think my friend Susan has 3 dogs and Mike has 8 fishes"

我想编写正则表达式来提取它后面的模式名称动词和#of 宠物以及它是什么种类的宠物。

re.findall('[A-Za-z]+ \w+ \d+ \w+', string)

适用于 Susan has 3 dogs, Mike has 8 fishes。

但它不适用于 John has got 6 cats

如何编辑代码以使其在名称后查找一两个词？

提前致谢！

Answer 1

您可以使用非捕获组 (?:...) 和 {1,2} 来表示 1 到 2 次重复，如下所示

import re
string="John has got 6 cats but I think my friend Susan has 3 dogs and Mike has 8 fishes"
found=re.findall(r'[A-Z][a-z]+ (?:\w+ ){1,2}\d+ \w+', string)
print(found)

输出

['John has got 6 cats', 'Susan has 3 dogs', 'Mike has 8 fishes']

提取可选数量的单词

Extracting optional quantity of words

python

regex

findall