如何过滤数字数组并采取一定的间隔？

Question

我有这种数组。

[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24]

过滤数组的要求是

每 4 项省略一次
取以下4件

并继续直到数组的末尾。

最后应该是return[5,6,7,8,13,14,15,16,21,22,23,24]

Answer 1

const values = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24];
newValues = values.filter((v, i) => i % 8 > 3)
console.log(newValues)

Answer 2

您可以将块切片并添加到结果数组。

const
    data = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24],
    result = [];
    
let i = 0;
while (i < data.length) result.push(...data.slice(i += 4, i += 4));

console.log(...result);

Answer 3

您可以创建一个分区函数来实现您的结果。

const arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24];

/**
 * Pertition the array and create a new array.
 *
 * @param {array}  arr The array to pertition.
 * @param {number} skip The number of elements to skip
 * @param {number} take Take the number of elements need to take after skipping.
 *
 * @return {array} The resulting array after pertition.
*/
const arrayAfterPertition = (arr, skip, take) => {
  const length = arr.length;
  let ans = [];
  
  /** If there are not enough elements to skip then returns empty array */
  if (length <= skip) return [];
  
  let takeIndex = skip;
  
  while (takeIndex < length) {
    ans = [...ans, ...arr.slice(takeIndex, takeIndex + take)];
    takeIndex = takeIndex + take + skip;
  }
  
  return ans;
}

console.log(JSON.stringify(arrayAfterPertition(arr, 4, 4)));

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Answer 4

Lodash 如果你不介意的话。使用 Loash#chunk

const nums = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24];

const chunkSize = 4;
const result = _.chunk(nums, chunkSize)
  .filter((v,i) => i % 2 ===1)
  .flat();
  
console.log(result);

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<script src="https://cdn.jsdelivr.net/lodash/4.10.0/lodash.js"></script>

如何过滤数字数组并采取一定的间隔？

How to filter an array of numbers and take certain intervals?

javascript

arrays

data-structures