使用JS使用split组织数组

Question

我需要使用 split 函数组织我的数组并循环访问数组中的多个项目。

我有一个看起来像这样的数组

var arr = [
{
"name": "bob",
"date": "1-1-2018",
"statistic": [
      "some title: 92nd (source, 2014)",
      "another title: 2.56 (source, 2014)",
      "title: 52.8% women (source, 2007/08)",
      "some title: 21.9% (source, 2016)",
      "another title: 3rd (source, 2016)"
    ]
},
{
"name": "sally",
"date": "1-1-2020",
"statistic": [
      "title: 8th (source, 2014)",
      "some title: 92nd (source, 2014)",
      "another: 40.8% women (source, 2007/08)",
      "some title: 21.9% (source, 2016)",
      "another title: 3 children (source, 2016)",
      "some title: 23rd (source, 2016)"
      "title: 46% (source, 2016)"
    ]
},
{
"name": "chris",
"date": "1-1-2021",
"statistic": [
      "some title: 46th (source, 2014)",
      "another title: 92nd (source, 2014)",
      "title: 52.8% women/children (source, 2007/08)"
    ]
},
//etc...
]

这是我试过的

 for (let i=0; i < arr.length; i++) {
    for (let x=0; x < arr.length; x++) {
      arr[i].custom = {};
      arr[i].custom["statistics"] = [];
    var s = arr[i].statistic[x].split("(");
    console.log(unit);
    var l = s[0].split(":");
    var u = l[1].split(" ");

    arr[i].custom["statistics"].push({
      number: u[1],
      suffix: u[0],
      label: l[0],
      source: s[1]

    });
  }
}

如何使我的代码看起来像这样？

var arr = [
{
"name": "bob",
"date": "1-1-2018",
"statistic": [
      "some title: 92nd (source, 2014)",
      "another title: 2.56 (source, 2014)",
      "title: 52.8% women (source, 2007/08)",
      "some title: 21.9% (source, 2016)",
      "another title: 3rd (source, 2016)"
    ],
"custom": {
      "statistics": [
{
    "number": "92nd",
    "suffix": "",
    "label": "some title",
    "source": "source, 2014)"
  },
  {
    "number": "2.56",
    "suffix": "",
    "label": "another title",
    "source": "CIA, 2017)"
  },
  {
    "number": "52.8%",
    "suffix": "women",
    "label": "title",
    "source": "source, 2007/08)"
  },
  {
    "number": "21.9%",
    "suffix": "",
    "label": "some title",
    "source": "source, 2016)"
  },
  {
    "number": "3rd",
    "suffix": "",
    "label": "another title",
    "source": "source, 2016)"
  }
],
etc...
}
},

]

当我知道数组中有内容时，它告诉我“arr[i].statistic[x]”返回未定义。我稍后可以修复左括号并将其设为“来源”：“（来源，2014）”

提前致谢

Answer 1

您正在迭代外部数组两次，而不是迭代内部循环中的每个项目 statistic。尝试使用

for (let i=0; i < arr.length; i++) {
  arr[i].custom = {};
  arr[i].custom["statistics"] = [];
  for (let x=0; x < arr[i].statistic.length; x++) {
// … further code …

代替你的循环。

此外，由于我没有足够的声誉来发表评论，有一个问题：您是否故意记录一个从未定义过的变量 unit？也许你可能想要记录 s?

Answer 2

您的循环没有正确嵌套，您的第二个循环没有遍历正确的项目。您每次都在重新创建 [statistics] 数组，因此只会得到其中的最后一项。

var arr = [{
    "name": "bob",
    "date": "1-1-2018",
    "statistic": [
      "some title: 92nd (source, 2014)",
      "another title: 2.56 (source, 2014)",
      "title: 52.8% women (source, 2007/08)",
      "some title: 21.9% (source, 2016)",
      "another title: 3rd (source, 2016)"
    ]
  },
  {
    "name": "sally",
    "date": "1-1-2020",
    "statistic": [
      "title: 8th (source, 2014)",
      "some title: 92nd (source, 2014)",
      "another: 40.8% women (source, 2007/08)",
      "some title: 21.9% (source, 2016)",
      "another title: 3 children (source, 2016)",
      "some title: 23rd (source, 2016)",
      "title: 46% (source, 2016)"
    ]
  },
  {
    "name": "chris",
    "date": "1-1-2021",
    "statistic": [
      "some title: 46th (source, 2014)",
      "another title: 92nd (source, 2014)",
      "title: 52.8% women/children (source, 2007/08)"
    ]
  }
]


for (let i = 0; i < arr.length; i++) {
  arr[i].custom = {};
  arr[i].custom["statistics"] = [];
  for (let x = 0; x < arr[i].statistic.length; x++) {
    var s = arr[i].statistic[x].split("(");
    var l = s[0].split(":");
    var u = l[1].split(" ");
    arr[i].custom["statistics"].push({
      number: u[1],
      suffix: u[0],
      label: l[0],
      source: s[1].substr(0, s[1].length - 1)

    });
  }
}
console.log(arr)

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