如何取新号和运行一样的过程python

Question

我正在尝试编写一个脚本来计算著名的“3x+1”等式，我希望 python 由用户输入一个数字，然后确定它是偶数还是奇数。如果偶数除以一半，如果奇数则做 3x+1，然后取经过这个过程的新数字，再做一次，直到数字变成 4。除了采用新编号并重复该过程的部分外，我已完成所有部分并正常工作。有谁知道我怎样才能得到这个来获取创建的新号码并重复这个过程。（对于那些想知道为什么我做了这么多次的人，我想不出一个名字，我的猫就在我旁边喵喵叫吃东西，所以我就跟着它去了）代码：

meow = 0
num = int(input("Enter a number"))
meow += 1
while True:
    if num == 4:
        print("you are now caught in a loop. (4 becomes 2 which becomes 1 which becomes 4 ect)")
        print("it took this number",meow-1,"times to get caught in this uninevitable loop for all recorded numbers")
    else:
        if(num % 2 != 0):
            print(num*3+1)
        else:
            print(num/2)

Answer 1

只需更新 num 每次迭代：

meow = 0
num = int(input("Enter a number"))
meow += 1
while True:
    if num == 4:
        print("you are now caught in a loop. (4 becomes 2 which becomes 1 which becomes 4 ect)")
        print("it took this number",meow-1,"times to get caught in this uninevitable loop for all recorded numbers")
    else:
        if(num % 2 != 0):
            num = num*3+1
            print(num)
        else:
            num = num/2
            print(num)

如何取新号和运行一样的过程python

How to take a new number and run the same process python

python

math

loops