如何将整数列表转换为单值元组

Question

我写了一个代码从数据库中删除一些用户，但是它说 Incorrect number of bindings supplied. The current statement uses 1, and there are 4 supplied。

def delete_user(self, user_id):
    stmt = "DELETE FROM user WHERE user_id = (?)"
    args = user_id
    try:
        self.conn.executemany(stmt, (args,))
        self.conn.commit()
    except sqlite3.Error as e:
        logging.error(str(e))

我的部分主要代码：

    deleted_user = []
    deleted_user.append(1384995383)
    deleted_user.append(1667596031)
    deleted_user.append(1332658866)
    deleted_user.append(1295962235)

    print(deleted_user)
    db.delete_user(deleted_user)

我找到了这个答案：

我尝试使用tuple(user_id)将其转换为元组，但结果不是 I'm except

来源 deleted_user 列表：

[1384995383, 1667596031, 1332658866, 1295962235]

元组（user_id）后结果：

(1384995383, 1667596031, 1332658866, 1295962235)

我的期望：

[(1384995383,), (1667596031,), (1332658866,), (1295962235,)]

我尝试搜索，但找不到我想要的答案:(

Answer 1

试试这个：

deleted_user.append((1384995383,))

Answer 2

def delete_user_ids(self, user_ids):
    stmt = "DELETE FROM user WHERE user_id = (?)"
    try:
        self.conn.executemany(stmt, user_ids)
#                                   ^^^^^^^^

user_ids = []
user_ids.append((1384995383,))
user_ids.append((1667596031,))
user_ids.append((1332658866,))
user_ids.append((1295962235,))
delete_user_ids(user_ids)

如何将整数列表转换为单值元组

How to turn an interger list to single value tuples

python

sqlite

python-3.x