Django 通过 JSON 响应获取主键

Question

如何通过 JSON 响应发送每个对象的主键？我正在发送 json 响应以根据用户状态修改 table。一切正常，除了无法获得与每个用户关联的 PK。

目前正在发送除 PK 之外的所有值。

class UserByState(View):
page_limit = 100

def get_paginated_context(self, queryset, page, limit):
    if not page:    page = 1 
    
    if limit:   
        self.page_limit = limit  
    paginator = Paginator(queryset, self.page_limit)
    page_obj = paginator.get_page(page)
    serialized_page = serialize("json", page_obj.object_list)
    serialized_page = [obj["fields"] for obj in json.loads(serialized_page)]

    return {
        "data": serialized_page,
        "pagination": {
            "page": page,
            "limit": limit,
            "has_next": page_obj.has_next(),
            "has_prev": page_obj.has_previous(),
            "total": queryset.count()
        }
    }

def get(self, request, *args, **kwargs):
    user = self.request.user
    page = request.GET.get('page')
    limit = request.GET.get('limit')
    state = request.GET.get('state')
    
    queryset = User.objects.all()

    if state and state != "all":
        queryset = queryset.filter(state=state)

    to_return = self.get_paginated_context(queryset, page, limit)
    return JsonResponse(to_return, status = 200)

Answer 1

我觉得这个理解可能会失去一些价值

serialized_page = serialize("json", page_obj.object_list)

当您在这里拨打 ['fields'] 时：

serialized_page = [obj["fields"] for obj in json.loads(serialized_page)]

您只获得键 'fields' 的值。就像标准词典一样。

fields = {"first_name": "Dan", "last_name": "ram", "address": "6090 DRAGON WAY", "city": "CREST", "state": "CA", "zipcode": 91912}

试试看：

serialized_page = serialize("json", page_obj.object_list)
serialized_page = [{**obj["fields"], **{"pk": obj["pk"]}} for obj in json.loads(serialized_page)]

Django 通过 JSON 响应获取主键

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