如何在没有 Express 的情况下响应 Nodejs 中的动态内容

Question

      let reqBody = "";
      req
        .on("data", (chunk) => {
          reqBody += chunk.toString();
        })
        .on("end", () => {
        const body = new URLSearchParams(reqBody);
        res.end("ok");
        });

我试图在没有 Express 的情况下使用 NodeJS 访问请求的主体，但由于某些原因，我无法运行 res.end("ok");.

Answer 1

你也需要打电话给req.end()

检查Node.js文档 https://nodejs.org/api/http.html

With http.request() one must always call req.end() to signify the end of the request - even if there is no data being written to the request body

 let reqBody = "";
  req
    .on("data", (chunk) => {
      reqBody += chunk.toString();
    })
    .on("end", () => {
    const body = new URLSearchParams(reqBody);
    res.end("ok");
    });
   req.end();

如何在没有 Express 的情况下响应 Nodejs 中的动态内容

How to response dynamic content in Nodejs without Express

javascript

ajax

node.js