如何根据用户输入创建变量? (Python)
How do you create variables based on user input? (Python)
我想创建一个程序来自动化我的科学评估。这是代码:
from statistics import mean
import matplotlib.pyplot as plt
import numpy as np
independent = input("What is your independent variable?\nindependent(unit): ")
dependent = input("What is your dependent variable?\ndependent(unit): ")
intervals = [int(x) for x in input(f"\nWhich {independent} values are you measuring? \nPlease seperate your answers with commas.: ").split(', ')]
try:
intervals[0]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results1 = [int(x) for x in input(f"What are the results of {intervals[0]}: ").split(', ')]
try:
intervals[1]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results2 = [int(x) for x in input(f"What are the results of {intervals[1]}: ").split(', ')]
try:
intervals[2]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results3 = [int(x) for x in input(f"What are the results of {intervals[2]}: ").split(', ')]
try:
intervals[3]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results4 = [int(x) for x in input(f"What are the results of {intervals[3]}: ").split(', ')]
try:
intervals[4]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results5 = [int(x) for x in input(f"What are the results of {intervals[4]}: ").split(', ')]
# processing data
def average(a):
return mean(a)
def range(list):
list.sort()
min = list[0]
max = list[-1]
return max - min
print(f"\nThe average of {intervals[0]} is {average(results1)}. The Range is {range(results1)}")
print(f"\nThe average of {intervals[1]} is {average(results2)}. The Range is {range(results2)}")
print(f"\nThe average of {intervals[2]} is {average(results3)}. The Range is {range(results3)}")
print(f"\nThe average of {intervals[3]} is {average(results4)}. The Range is {range(results4)}")
print(f"\nThe average of {intervals[4]} is {average(results5)}. The Range is {range(results5)}")
# graphing
y = np.array(intervals)
x = np.array([average(results1), average(results2), average(results3), average(results4), average(results5)])
xerrorbars = [range(results1) / 2, range(results2) / 2, range(results3) / 2, range(results4) / 2, range(results5) / 2]
def give_me_a_straight_line(x,y):
w, b = np.polyfit(x,y,deg=1)
line = w * x + b
return line
line = give_me_a_straight_line(x,y)
plt.plot(x,y,'o')
plt.plot(x,line,'r--')
plt.errorbar(x, y, xerr=xerrorbars, fmt="o", color="blue")
plt.ylabel(independent)
plt.xlabel(dependent)
plt.grid()
plt.show()
如您所见,我添加了错误消息,以防用户在可变间隔中输入少于或多于 5 个项目。这使得该程序仅在输入 5 个项目时可用。这很糟糕,因为有时您可能只想使用 4 或 3 个间隔。有没有办法根据列表间隔中的项目创建多个变量?
使用列表而不是普通变量。
minVals = 5
if len(intervals) < minVals:
raise IndexError(f"Please enter at least 5 {independent} values")
results = []
for interval in intervals:
results.append([int(x) for x in input(f"What are the results of {intervals[0]}: ").split(', ')])
def valRange(list): # range() is an existing Python function which you should not redefine.
list.sort()
min = list[0]
max = list[-1]
return max - min
x = np.array([mean(result) for result in results])
xerrorbars = [valRange(result) / 2 for result in results]
print(f"\nThe average of {intervals[0]} is {average(results[0])}.")
虽然您可以创建变量名称,但大多数时候这是一个糟糕的想法,因为它会使您的命名空间变得混乱,使它成为 debug/modify 和其他讨厌的东西的噩梦。
大多数时候列表和字典会用更干净的代码做同样的事情。
我想创建一个程序来自动化我的科学评估。这是代码:
from statistics import mean
import matplotlib.pyplot as plt
import numpy as np
independent = input("What is your independent variable?\nindependent(unit): ")
dependent = input("What is your dependent variable?\ndependent(unit): ")
intervals = [int(x) for x in input(f"\nWhich {independent} values are you measuring? \nPlease seperate your answers with commas.: ").split(', ')]
try:
intervals[0]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results1 = [int(x) for x in input(f"What are the results of {intervals[0]}: ").split(', ')]
try:
intervals[1]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results2 = [int(x) for x in input(f"What are the results of {intervals[1]}: ").split(', ')]
try:
intervals[2]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results3 = [int(x) for x in input(f"What are the results of {intervals[2]}: ").split(', ')]
try:
intervals[3]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results4 = [int(x) for x in input(f"What are the results of {intervals[3]}: ").split(', ')]
try:
intervals[4]
except IndexError:
raise IndexError(f"PLease enter at least 5 {independent} values") from None
results5 = [int(x) for x in input(f"What are the results of {intervals[4]}: ").split(', ')]
# processing data
def average(a):
return mean(a)
def range(list):
list.sort()
min = list[0]
max = list[-1]
return max - min
print(f"\nThe average of {intervals[0]} is {average(results1)}. The Range is {range(results1)}")
print(f"\nThe average of {intervals[1]} is {average(results2)}. The Range is {range(results2)}")
print(f"\nThe average of {intervals[2]} is {average(results3)}. The Range is {range(results3)}")
print(f"\nThe average of {intervals[3]} is {average(results4)}. The Range is {range(results4)}")
print(f"\nThe average of {intervals[4]} is {average(results5)}. The Range is {range(results5)}")
# graphing
y = np.array(intervals)
x = np.array([average(results1), average(results2), average(results3), average(results4), average(results5)])
xerrorbars = [range(results1) / 2, range(results2) / 2, range(results3) / 2, range(results4) / 2, range(results5) / 2]
def give_me_a_straight_line(x,y):
w, b = np.polyfit(x,y,deg=1)
line = w * x + b
return line
line = give_me_a_straight_line(x,y)
plt.plot(x,y,'o')
plt.plot(x,line,'r--')
plt.errorbar(x, y, xerr=xerrorbars, fmt="o", color="blue")
plt.ylabel(independent)
plt.xlabel(dependent)
plt.grid()
plt.show()
如您所见,我添加了错误消息,以防用户在可变间隔中输入少于或多于 5 个项目。这使得该程序仅在输入 5 个项目时可用。这很糟糕,因为有时您可能只想使用 4 或 3 个间隔。有没有办法根据列表间隔中的项目创建多个变量?
使用列表而不是普通变量。
minVals = 5
if len(intervals) < minVals:
raise IndexError(f"Please enter at least 5 {independent} values")
results = []
for interval in intervals:
results.append([int(x) for x in input(f"What are the results of {intervals[0]}: ").split(', ')])
def valRange(list): # range() is an existing Python function which you should not redefine.
list.sort()
min = list[0]
max = list[-1]
return max - min
x = np.array([mean(result) for result in results])
xerrorbars = [valRange(result) / 2 for result in results]
print(f"\nThe average of {intervals[0]} is {average(results[0])}.")
虽然您可以创建变量名称,但大多数时候这是一个糟糕的想法,因为它会使您的命名空间变得混乱,使它成为 debug/modify 和其他讨厌的东西的噩梦。
大多数时候列表和字典会用更干净的代码做同样的事情。