根据内部数组对数组进行排序

Question

我想根据按字母顺序排序的内部数组值对数组进行排序。例如。

我希望这个数组按前缀“old”排序，如旧 A、旧 B 等

const array = [
  { personName: "Vans", personTags: ["young",  "old A"] },
  { personName: "Lia", personTags: ["young",  "ok"] },
  { personName: "Rein", personTags: ["old B", "hairless", "ok"] },
  { personName: "Cris", personTags: ["old A",  "old B", "acrounimouslyness"] },
  { personName: "Mercy", personTags: ["young", "hairless", "ok"] },
  { personName: "Cbum", personTags: ["old C", "hairless", "young"] },
];

变成

const array = [
  { personName: "Vans", personTags: ["young",  "old A"] },
  { personName: "Cris", personTags: ["old A",  "old B", "acrounimouslyness"] },
  { personName: "Rein", personTags: ["old B", "hairless", "ok"] },
  { personName: "Cbum", personTags: ["old C", "hairless", "young"] },
];

//将被删除

{ personName: "Lia", personTags: ["young", "ok"] }, { personName: "Mercy", personTags: ["young", "hairless", "ok"] },

Answer 1

你可以filter then sort:

const array = [
  { personName: "Vans", personTags: ["young", "old A"] },
  { personName: "Lia", personTags: ["young", "ok"] },
  { personName: "Rein", personTags: ["old B", "hairless", "ok"] },
  { personName: "Cris", personTags: ["old B", "old A", "acrounimouslyness"] },
  { personName: "Mercy", personTags: ["young", "hairless", "ok"] },
  { personName: "Cbum", personTags: ["old C", "hairless", "young"] },
];

const getFirstOldElement = arr => {
  return arr
    .filter(s => s.startsWith("old"))
    .sort()
    .at(0);
};

const newArray = array
  .filter(
    obj =>
      (obj.personTags || []).findIndex(s => s.startsWith("old")) !== -1
  )
  .sort((a, b) =>
    getFirstOldElement(a.personTags).localeCompare(getFirstOldElement(b.personTags))
  );

console.log(newArray);

Answer 2

使用 Array#reduce, iterate over the array while updating an array of elements having an old tag. In each iteration, get the list of old tags using Array#filter and String#startsWith. If the list is not empty, push a new object to the accumulator with a special property sortedOldTags which is basically the current old tags sorted (using Array#sort, String#localeCompare, and Array#join).
使用Array#sort，使用特殊的属性.
使用Array#map，return排序列表从每个元素中取出特殊属性。

const array = [
  { personName: "Vans", personTags: ["young",  "old A"] },
  { personName: "Lia", personTags: ["young",  "ok"] },
  { personName: "Rein", personTags: ["old B", "hairless", "ok"] },
  { personName: "Cris", personTags: ["old A",  "old B", "acrounimouslyness"] },
  { personName: "Mercy", personTags: ["young", "hairless", "ok"] },
  { personName: "Cbum", personTags: ["old C", "hairless", "young"] },
];

const arrWithSortProp = array.reduce((arr, e) => {
  const { personTags = [] } = e;
  const oldTags = personTags.filter(tag => tag.startsWith("old"));
  if(oldTags.length) {
    arr.push({ 
      ...e, 
      sortedOldTags: oldTags.sort((a, b) => a.localeCompare(b)).join() 
    });
  }
  return arr;
}, []);

const sorted = arrWithSortProp
  .sort(({ sortedOldTags: a }, { sortedOldTags: b }) => a.localeCompare(b))
  .map(({ sortedOldTags, ...e }) => e);

console.log(sorted);

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