读取 headers 在数据单元内的 csv

Question

我想在 Python 中导入格式如下的 csv：

with open('categories.csv', 'r') as file:
    reader = csv.reader(file)
    for row in reader:
        print(row)

['id', 'categories']
['2', 'related-1;request-0;offer-0;aid_related-0;medical_help-0;medical_products-0;search_and_rescue-0;security-0;military-0;child_alone-0;water-0;food-0;shelter-0;clothing-0;money-0;missing_people-0;refugees-0;death-0;other_aid-0;infrastructure_related-0;transport-0;buildings-0;electricity-0;tools-0;hospitals-0;shops-0;aid_centers-0;other_infrastructure-0;weather_related-0;floods-0;storm-0;fire-0;earthquake-0;cold-0;other_weather-0;direct_report-0']
['7', 'related-1;request-0;offer-0;aid_related-1;medical_help-0;medical_products-0;search_and_rescue-0;security-0;military-0;child_alone-0;water-0;food-0;shelter-0;clothing-0;money-0;missing_people-0;refugees-0;death-0;other_aid-1;infrastructure_related-0;transport-0;buildings-0;electricity-0;tools-0;hospitals-0;shops-0;aid_centers-0;other_infrastructure-0;weather_related-1;floods-0;storm-1;fire-0;earthquake-0;cold-0;other_weather-0;direct_report-0']

最后，数据框应该是这样的：

ID related request  ...
 2       1       0  ...
 7       1       0  ...

Answer 1

您可以考虑使用pandas:

import pandas

df = pd.read_csv('./text.csv')
# get and expand columns
columns = [i.split('-')[0] for i in df['categories'].str.split(';')[0]]
df[columns] = df['categories'].str.split(';', expand=True)
# drop categories column
df.drop('categories', axis=1, inplace=True)
# get value for each column
for column in columns:
    df[column] = df[column].apply(lambda x : x.split('-')[1])
print(df)

读取 headers 在数据单元内的 csv

Read csv where headers are inside the datacells

python

csv

dataframe

pandas