问题排序列表，列表乱序

Question

嗨，我正在尝试使用 python 和 pytq5 编写一个基本的 GUI，它显示从 API 调用接收到的信息，当信息从 API 它返回时似乎出了问题，我不知道如何在将数据发送到 GUI 之前对数据进行排序，该列表是字典列表，

interfaces = [
        {'name': 'GigabitEthernet 0/0'},
        {'name': 'GigabitEthernet 1/0/1'},
        {'name': 'GigabitEthernet 1/0/10'},
        {'name': 'GigabitEthernet 1/0/11'},
        ...        
        ]

任何建议将不胜感激，从图像中我希望对数据进行排序，以便 1/0/1 - 1/0/9 都在 1/0/10 之前

谢谢

Answer 1

试试这个：

# Your list of dicts
interfaces = [
    {'name': 'GigabitEthernet 0/0'},
    {'name': 'GigabitEthernet 1/0/11'},
    {'name': 'GigabitEthernet 1/0/10'},
    {'name': 'GigabitEthernet 1/0/1'},
    {'name': 'GigabitEthernet 1/0/2'}
]

new_interfaces = []
# Create a list of dicts whose value corresponding to the 'name' key would be a list
# containing the ethernet type (in this case, 'GigabitEthernet') and a list of 3
# elements representing the date (like '[1, 0, 11]')
for entry in [i["name"] for i in interfaces]:
    new_interfaces.append({'name': [entry.split()[0], entry.split()[1].split("/")]})

# If one of those lists representing the date contains 2 elements, add a third
# element with a value of '0'
for entry in new_interfaces:
    if len(entry['name'][1]) == 2:
        entry['name'][1].append('0')

# Sort the list according to the date
new_interfaces = sorted(new_interfaces, key=lambda d: int(''.join(d['name'][1])))

# Re-create the original list with sorted values and original structure
interfaces = []
for entry in new_interfaces:
    interfaces.append({'name': f"{entry['name'][0]} {'/'.join(entry['name'][1])}"})
print(interfaces)

输出：

[{'name': 'GigabitEthernet 0/0/0'}, {'name': 'GigabitEthernet 1/0/1'}, {'name': 'GigabitEthernet 1/0/2'}, {'name': 'GigabitEthernet 1/0/10'}, {'name': 'GigabitEthernet 1/0/11'}]

此算法将日期（或任何它是 lol）转换为不带 '/' 的字符串，以便它可以转换为整数以便能够正确地相互比较。

示例：

1/0/10 将是 1010

1/0/1 将是 101

并且由于 101 小于 1010 作为数字，sorted() 方法将其放在前面。

问题排序列表，列表乱序

Issues Sorting a list, list out of order

sorting

list

python-3.x

示例：